3 years ago

Tina and her puppy are tugging on a rope, each pulling on opposite ends.

Physics

2 answers:

pickupchik [31]3 years ago

8 0

B. whenever she pulls the puppy toward her..

timama [110]3 years ago

5 0

B. whenever she pulls the puppy toward her.

You might be interested in

a planes average speed between two cities is 600 km/hr. if he takes 2.5 hrs. how far does the plane fly

o-na [289]

Answer:

1500 hr

..............

4 0

2 years ago

A train travels 65 kilometers in 5 hours, and then 61 kilometers in 4 hours. What is its average speed? _______km/hr

olasank [31]

The trains average speed is 13 km/hr.

4 0

3 years ago

Read 2 more answers

___________ are over 500 million years old and have been developing their unique system all that time.

zhannawk [14.2K]

Answer:

Explanation:

3 0

2 years ago

Read 2 more answers

What are parts of a pulley

PtichkaEL [24]

Wheel, axel and rope

3 0

2 years ago

A) A spaceship passes you at a speed of 0.800c. You measure its length to be 31.2 m .How long would it be when at rest?

rosijanka [135]

Answer:

$l_o =52 \ m$

$l = 37.13 \ LY$

Explanation:

From the question we are told that

The speed of the spaceship is $v = 0.800c$

Here c is the speed of light with value $c = 3.0*10^{8} \ m/s$

The length is $l = 31.2 \ m$

The distance of the star for earth is $d = 145 \ light \ years$

The speed is $v_s = 2.90 *10^{8}$

Generally the from the length contraction equation we have that

$l = l_o \sqrt{1 -[\frac{v}{c } ]}$

Now the when at rest the length is $l_o$

$l_o =\frac{l}{\sqrt{ 1 - \frac{v^2}{c^2 } } }$

$l_o =\frac{ 31.2 }{ \sqrt{1 - \frac{(0.800c ) ^2}{c^2} } }$

$l_o=52 \ m$

Considering b

Applying above equation

$l =l_o \sqrt{1 - [\frac{v}{c } ]}$

Here $l_o =145 \ LY(light \ years )$

$l=145 * \sqrt{1 - \frac{v_s^2}{c^2 } }$

$l =145 * \sqrt{ 1 - \frac{2.9 *10^{8}}{3.0*10^{8}} }$

$l = 37.13 \ LY$

4 0

3 years ago