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kicyunya [14]
3 years ago
13

If the distance between the first order maximum and the tenth order maximum of a double-slit pattern is 18 mm and the slits are

separated by 0.15 mm with the screen 50 cm from the slits, what is the wavelength of the light used
Physics
1 answer:
Setler79 [48]3 years ago
4 0

Answer:

Wavelength of light is 600 nm

Explanation:

Given

Distance between the first order maximum and the tenth order maximum of a double-slit pattern = 18 mm

Separation between the slits = 0.15 mm

Distance of screen from the slits = 50 cm

Wavelength

= \frac{18*10^{-3} * 0.15 *10^{-3}}{0.50*9} \\= 6 *10^{-7}\\= 600nm

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Water from a leaking tap begins to fall into
Amanda [17]

Answer:

It will take 20,000 seconds to get a pressure of 200Pa at the bottom of the tank.

Explanation:

The pressure at the bottom of the tank will be

P = \dfrac{Mg}{A}

where M is the mass of the water, and A is the base area of the tank.

The base area of the tank is

A = 0.5m* 2m = 1m^2,

and if we want the pressure at the bottom to be 200pa, then it must be that

200Pa = \dfrac{M(10m/s^2)}{1m^2},

solving for M we get:

M = 20kg\\

which is the required mass of the water in the tank.

Now, the tank fills at a rate of 2 drops per second or

2 (0.05g)/s = 0.10g/s = 0.0001kg/s

since each drop weights 0.05g.

Therefore, the time t it takes to collect 20kg of water will be

t = 20kg \div \dfrac{0.0001kg}{s}

t = 2*10^5s

which is 55.56 hours or 2 days and 7.56 hours.

Thus, it will take 20,000 seconds to get a pressure of 200Pa at the bottom of the tank.

7 0
3 years ago
Please help with this question! Thanks in advance...
-Dominant- [34]

A.0.6 hope you do good on your test!!

5 0
3 years ago
The gravitational force acting on various masses is measured on different planets. Measured values for the forces acting on the
tatyana61 [14]

we Know that gravitational field strength(g) at a point on a planet  is equal to  gravitational force exerted per unit mass placed at that point.

It Means,

g=F/m

Here,

g=gravitational field strength

F=Gravitational force

m=Mass

Case A

planet force =10 and mass= .5

g1=F/m

g1=10/.5

=100/5

g1=20m/s

case B

F=30 and m=2

therefore g2=30/2

g2=15m/s^2

case C

F=45 and m=3

g3=45/3

=15m/s^2

case D

g4=60/6

g4=10m/s^2

from above results it is clear that the gravitational field strength of planet D is minimum which is 10m/s^2 and gravitational field strength of planet A is maximum which is 20m/s^2

5 0
4 years ago
A ball is thrown upward at a velocity of 20m/s. What is the velocity after 3 seconds?
Anit [1.1K]

This is a perfect problem to use positive and negative velocities.

Let's call the positive direction the direction that points UP. 
Then the negative direction is the one that points down.

The acceleration of gravity on Earth is 9.8 m/s² down.  That means
that any object with no forces on it except gravity gains 9.8 m/s of
speed downward every second.

OK. Ready to go to work:

The ball's initial velocity is +(up)20.0 m/s .
Every second after the toss, the ball has -(down)9.8 m/s more velocity.

The ball's velocity after 3 seconds is

            +20 + 3(-9.8)  = 

              20  -  29.4  =    - 9.4 m/s .

That means it's velocity at that time is  9.4 m/s pointing down.

6 0
3 years ago
What is the speed of the pulley A if pully D is moving at a speed of 8 km/h​
Serhud [2]

Answer:

hey I know the answer for this

Explanation:

it will be reduce the speed of A

the answer is 7.

this is the exact answer.

if you don't like this answer means pls comment me

3 0
3 years ago
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