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kicyunya [14]
2 years ago
13

If the distance between the first order maximum and the tenth order maximum of a double-slit pattern is 18 mm and the slits are

separated by 0.15 mm with the screen 50 cm from the slits, what is the wavelength of the light used
Physics
1 answer:
Setler79 [48]2 years ago
4 0

Answer:

Wavelength of light is 600 nm

Explanation:

Given

Distance between the first order maximum and the tenth order maximum of a double-slit pattern = 18 mm

Separation between the slits = 0.15 mm

Distance of screen from the slits = 50 cm

Wavelength

= \frac{18*10^{-3} * 0.15 *10^{-3}}{0.50*9} \\= 6 *10^{-7}\\= 600nm

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Because the earth's orbit is slightly elliptical, the earth actually gets closer to the sun during part of the year. When the ea
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Closer to the sun . . . orbital speed is faster.

Farther from the sun . . . orbital speed is slower.

Flag answer:  Answer 13  Answer 13

5 0
2 years ago
The transverse standing wave on a string fixed at both ends is vibrating at its fundamental frequency of 250 Hz. What would be t
hodyreva [135]

Answer:

Explanation:

fundamental frequency, f = 250 Hz

Let T be the tension in the string and length of the string is l ans m be the mass of the string initially.

the formula for the frequency is given by

f=\frac{1}{2l}\sqrt{\frac{Tl}{m}}    .... (1)

Now the length is doubled ans the tension is four times but the mass remains same.

let the frequency is f'

f'=\frac{1}{2\times 2l}\sqrt{\frac{4T\times 2l}{m}}    .... (2)

Divide equation (2) by equation (1)

f' = √2 x f

f' = 1.414 x 250

f' = 353.5 Hz

7 0
3 years ago
A ball is thrown vertically upwards with an initial velocity of 20.00 m/s. Neglecting air resistance, how long is the ball in th
algol [13]

Answer:

1) The greatest height attained by the ball equals 20.387 meters.

2) The time it takes for the ball to reach 15 meters approximately equals 1 second.

Explanation:

The greatest height will be attained when the ball stop's in the air and starts falling back to the earth.

thus using third equation of kinematics we obtain the height attained as

v^2=u^2+2as

where

'v' is the final speed of the ball

'u' is the initial speed of the ball

'a' is the acceleration that the ball is under which in this case equals 9.81 m/s^{2}

's' is the distance it covers

Thus for maximum height applying the values in the equation we get

0=20^{2}-2\times 9.81\times h\\\\\therefore h=\frac{20^{2}}{2\times 9.81}=20.387meters

Using the same equation we can find the speed of the ball when it reaches 15 meters of height as  

v^2=20^{2}-2\times 9.81\times 15\\\\v^{2}=105.7\\\\\therefore v=10.28m/s

the time it takes to reduce the velocity to this value can be found by first equation of kinematics as

v=u+at\\\\t=\frac{v-u}{a}\\\\t=\frac{10.28-20}{-9.81}=0.991seconds\approx 1second

4 0
3 years ago
Which planet has a moon with many sulfur volcanoes?
Murljashka [212]

Jupiter i hope it is right answer

6 0
2 years ago
Which of the following factors most affect the rate at which waves erode land features along the shore?
OLEGan [10]

Answer:

The biggest factor affecting coastal erosion is the strength of the waves breaking along the coastline. A wave's strength is controlled by its fetch and the wind speed. Longer fetches & stronger winds create bigger, more powerful waves that have more erosive power.

Explanation:

hope it helps !

5 0
2 years ago
Read 2 more answers
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