1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kicyunya [14]
3 years ago
13

If the distance between the first order maximum and the tenth order maximum of a double-slit pattern is 18 mm and the slits are

separated by 0.15 mm with the screen 50 cm from the slits, what is the wavelength of the light used
Physics
1 answer:
Setler79 [48]3 years ago
4 0

Answer:

Wavelength of light is 600 nm

Explanation:

Given

Distance between the first order maximum and the tenth order maximum of a double-slit pattern = 18 mm

Separation between the slits = 0.15 mm

Distance of screen from the slits = 50 cm

Wavelength

= \frac{18*10^{-3} * 0.15 *10^{-3}}{0.50*9} \\= 6 *10^{-7}\\= 600nm

You might be interested in
Imvu?<br> ..............................
Dominik [7]
Imvu? Like the app?
4 0
3 years ago
Read 2 more answers
A bowl contains 4 red balls and 2 green balls. Two balls are selected simultanesouly and at random. What is the conditional prob
AlladinOne [14]

Answer:0.6

Explanation:

Given

Bowl contains 4 red and 2 Green balls

Probability of selecting two red balls given atleast one of the ball is red + Probability of selecting two red balls given that no ball is red =1

Probability of selecting two red balls given that no ball is red =\frac{Probability \ of\ selecting\ two\ red\ balls\ out\ of\ 4\ balls}{probability\ of\ selecting\ 2\ balls\ out\ of\ 6 balls}

P=\frac{^{4}C_2}{^{6}C_2}

P=\frac{2}{5}

Required Probability=1-\frac{2}{5}=\frac{3}{5}

7 0
4 years ago
The length and mass of the arm are Larm = X1 = 50 cm and Marm = 0.3 kg, X2 = 15 cm, and the mass of the object is MObject = 0.25
max2010maxim [7]

Answer: 0.5N

Explanation: if the system is at equilibrium, sum of the torque will be equal to zero.

But if they are not in equilibrium.

U will find the difference in the two torque

find the attached file for solution

3 0
3 years ago
An 80-kg quarterback jumps straight up in the air right before throwing a 0.43-kg football horizontally at 15 m/s . Suppose that
RUDIKE [14]

Answer:

0.0241875 m

Explanation:

m_1 = Mass of quarterback = 80 kg

m_2 = Mass of football = 0.43 kg

v_1 = Velocity of quarterback

v_2 = Velocity of football = 15 m/s

Time taken = 0.3 seconds

In this system as the linear momentum is conserved

m_1v_1+m_2v_2=0\\\Rightarrow v_1=-\frac{m_2v_2}{m_1}\\\Rightarrow v_1=-\frac{0.43\times 15}{80}\\\Rightarrow v_1=0.080625\ m/s

Assuming this velocity is constant

Distance=Velocity\times Time\\\Rightarrow Distance=0.080625\times 0.3\\\Rightarrow Distance=0.0241875\ m

The distance the quarterback will move in the horizontal direction is 0.0241875 m

4 0
3 years ago
What are the (time varying) amplitudes of the E and H fields if summer sunlight has an intensity of 1150 W/m2 in any Town?
Archy [21]

Explanation:

Given that,

Intensity = 1150 W/m²

(a). We need to calculate the magnetic field

Using formula of intensity

I=\dfrac{E^2}{2\mu_{0}c}

E=\sqrt{2\times I\mu_{0}c}

Put the value into the formula

E=\sqrt{2\times1150\times4\pi\times10^{-7}\times3\times10^{8}}

E=931.17\ N/C

Using formula of magnetic field

B = \dfrac{E}{c}

Put the value into the formula

B=\dfrac{931.17}{3\times10^{8}}

B=0.0000031039\ T

B=3.10\times10^{-6}\ T

(b). The relative strength of the gravitational and solar electromagnetic pressure forces of the sun on the earth

We need to calculate the gravitational force

Using gravitational force

F=\dfrac{Gm_{s}M_{e}}{r^2}

Put the value into the formula

F=\dfrac{6.67\times10^{-11}\times1.98\times10^{30}\times5.97\times10^{24}}{(1.496\times10^{11})^2}

F=3.522\times10^{22}\ N

We need to calculate the radiation force

Using formula of force

F_{R}=\dfrac{I}{c}\pi\timesR_{E}^{2}

Put the value into the formula

F_{R}=\dfrac{1150}{3\times10^{8}}\times\pi\times(6.378\times10^{6})^2

F_{R}=4.8\times10^{8}\ N

The gravitational and solar electromagnetic pressure forces of the sun on the earth

\dfrac{F_{G}}{F_{R}}=\dfrac{3.522\times10^{22}}{4.8\times10^{8}}

\dfrac{F_{G}}{F_{R}}=7.3375\times10^{13}

Hence, This is the required solution.

3 0
3 years ago
Other questions:
  • The picture on the left represents the reactants in the equation and the picture on the right represents the products. Does this
    9·1 answer
  • A flagpole consists of a flexible, 7.107.10 m tall fiberglass pole planted in concrete. The bottom end of the flagpole is fixed
    15·1 answer
  • a uniform electric field E=15 N/C points downwards. A particle with charge q=-0.15 C is placed in the electric field. What is th
    7·1 answer
  • When viewed in yellow light, an object that reflects all the colors of light will appear_____.
    15·1 answer
  • 1 kg ball rolls off a 33 m high cliff, and lands 23 m from the base of the cliff. Express the displacement and the gravitational
    7·1 answer
  • Why is a cell theory a theory and not a law
    9·1 answer
  • If the pH of a substance is 12.4, the substance is a _______
    14·1 answer
  • Please help me!!!!! ​
    13·1 answer
  • 1. Winds may be named for their location or for the direction from which they blow. Which winds blow from 30° latitude in both h
    15·1 answer
  • Water flows through a 4.50-cm inside diameter pipe with a speed of 12.5 m/s. At a later position, the pipe has a 6.25-cm inside
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!