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3 years ago

What is an abiotic factor in a squirrel's habitat that could be harmful if the factor changed

1 answer:

5 0

<span>Biotic and Abiotic Factors Form Ecosystems. In a healthy forest community, interacting populations might include birds eating insects, squirrels eating nuts from trees, mushrooms growing from decaying leaves or bark, and raccoons fishing in a stream. In addition to how individuals in a population interact with each other, let me know if it helps :)</span>

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If a shell can hold a maximum of 32 electrons, what is the value of n

just olya [345]

I think the answe would be 16n

5 0

3 years ago

What is the study of acid-base chemistry called in the environment

Charra [1.4K]

Answer:

An acid is a substance that donates protons (in the Brønsted-Lowry definition) or accepts a pair of valence electrons to form a bond (in the Lewis definition). A base is a substance that can accept protons or donate a pair of valence electrons to form a bond. Bases can be thought of as the chemical opposite of acids.

8 0

3 years ago

When the following equation is balanced, what is the coefficient of oxygen?

Gwar [14]

Answer:

The answer is 3

C2H5OH + O2 CO2 +H2O (unbalanced)

C2H5OH +3O2(g). 2CO2(g)+3H2O(balanced)

4 0

3 years ago

how many grams of phosphorus (P4) react with 35.5L of O2 at STP to form solid tetraphosphorus decaoxide

algol [13]

Answer:

mass P4 = 35.998 g

Explanation:

P4 + 5O2 → P4O10

∴ STP: P = 1 atm; T = 298 K

∴ V O2= 35.5 L

⇒ nO2 = P.V / R.T

∴ R = 0.082 atm.L/K.mol

⇒ nO2 = ((1 atm)×(35.5L))/((0.082 atm.L/K.mol)(298K))

⇒ nO2 = 1.453 mol O2

⇒ mol P4 = (1.453 molO2)×(mol P4/ 5molO2) = 0.2906 mol P4

∴ Mw P4 = 123.895 g/mol

⇒ mass P4 = (0.2906 mol P4)×(123.895 g/mol) = 35.998 g P4

4 0

3 years ago

Is 6.0 × 10 to the negative 4th power is a significant figure?

Dmitry_Shevchenko [17]

Answer:

Yes

Explanation:

First remember that a significant figure are basically values that contribute to the precision of a value. In any scientific notation the values are significant figures because these values stay the same. In this case we have two significant figures which is 6 and 0, you can further prove that they are significant figures by converting the notation into standard form.

$6.0\times10^{-4}$

Negative so move the decimal point to the left:

$=0.00060$

6 and 0 are the significant figures in this standard notation because it's precise to it's actual value which is 6.0.

To sum up, the values you have on the left side of a notation are significant figures since they will not change no matter if it's standard or scientific notation meaning it's precise.

Hope this helps.

6 0

2 years ago