All categories

3 years ago

At which temperature does the molecules of an object stop moving?

Physics

1 answer:

PilotLPTM [1.2K]3 years ago

7 0

Answer:

at the melting point and boiling point

Explanation:

the heat abdorbed is used to break down the forces holding the particles together to allow it to change its state

You might be interested in

A softball player moving 3.89 m/s

Ahat [919]

Answer:

0.119 s

Explanation:

Given that

$U=3.89\ m/s\\a=-1.44\ m/s^2\\S=4.8\ m$

Lets take final speed of the softball after covering 4.8 m = V

We know that

$V^2=U^2+2aS\\V^2=3.89^2-2\times 1.44\times 4.8\\V=3.7\ m/s$

Also We know that

$V=U+at\\$

Putting the value of V ,U and a in the previous equation We get

$3.7=3.89-1.44\times t\\t=0.119\ s$

Therefore slide time will be 0.119 s

3 0

4 years ago

Compared to the mass and charge of a proton, the electron has

maxonik [38]

B. opposite charge and smaller mass

8 0

4 years ago

Researchers conducted an experiment to identify the effects of three different hand sanitizers on the growth of bacteria. The re

pickupchik [31]

Picture ? I need a visual reference

7 0

3 years ago

Read 2 more answers

The time constant for RC circuit with the values of R1 and C1 is 5ms. What will be the time constant for a new RC circuit with t

lions [1.4K]

Answer:

d. 25 ms

Explanation:

In a RC circuit we call time constant to the product of the resistance times the capacitance, which represents the time when the charge reaches to the 63% of the final value, as follows:

$\tau_{1} = R_{1} *C_{1} = 5 ms (1)$

If we have a new circuit with new values for R and C, the time constant will be defined in the same way, as follows:

$\tau_{2} =10* R_{1} *0.5*C_{1} = 5*(R_{1}* C_{1}) = 5* \tau_{1} = 5* 5 ms = 25 ms (2)$

6 0

3 years ago

If the speed of sound in air is 343 m/s and the wavelength of this note is 2.62 m, what is the frequency of this C3 note? (Round

snow_lady [41]

Answer:

The frequency of of the note = 131 Hz.

Explanation:

Frequency: Frequency can be defined as the number of complete oscillation completed by a wave in one seconds. The S.I unit of frequency is Hertz ( Hz)

v = λf ............................ Equation 1

Making f the subject of the equation,

f = v/λ .......................... Equation 2

Where v = Speed, λ = wavelength, f = frequency

Given: v = 343 m/s, λ = 2.62 m.

Substituting these values into equation 2

f = 343/2.62

f = 131 Hz

Thus the frequency of of the note = 131 Hz.

8 0

3 years ago