Answer: D!
It is the option with the greatest amplitude.
The average electric current in the lightning will be 8 ×
A
<h3>
Why Lightning Conductors on top of a tower ?</h3>
The lightning conductors are long metal strips running from the spike end of a conductor on the top of a building to the earth. They are used to prevent buildings from destruction when struck by thunder or lightning.
Given that a lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms, to calculate the average electric current in the lightning, we will first consider the charge released.
one charge = 1.6 ×
C
Average current I = Q/t
Where
- Q = charge = 1.6 ×
C
- t = time = 2ms = 2 ×
s
Substitute all the parameters into the formula
I = 1.6 ×
C ÷ 2 × 
I = 8 ×
A
Therefore, the average electric current in the lightning will be 8 ×
A
Learn more about Lightning here: brainly.com/question/3183045
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The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
To find the answer, we have to know about the pressure.
<h3>How to find the weight of a column of air?</h3>
- As we know that the expression of pressure as,

where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.
- It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,

- From this, the value of weight will be,

Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
Learn more about the pressure here:
brainly.com/question/12830237
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All of them apply because they all are doing some thing to move