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agasfer [191]
1 year ago
3

Nfpa 70e, standard for electrical safety in the workplace, consists of ? chapters; 18 informative annexes; the foreword to nfpa

70e; and article 90, introduction. chapter 1 is divided into ? articles.
Physics
1 answer:
andrew11 [14]1 year ago
4 0

NFPA 70e consist of 3 chapters and the chapter 1 is divided into 5 articles.

<h3>What is NFPA?</h3>

The National Fire Protection Association is abbreviated as NFPA (NFPA). It has three chapters and seventeen annexes that contain standard electrical safety guidelines.

The NFPA 70E code covers safety management systems, equipment maintenance, and more specific requirements for specific equipment.

The goal of NFPA 70E®, Standard for Electrical Safety in the Workplace®, is to provide employees with a safe working environment free of unacceptable risk associated with the use of electricity in the workplace.

The first chapter of NFPA 70E discusses the parameters of an electrical safety program, whether used alone or as part of a comprehensive safety management system.

To learn more about NFPA 70e, refer to:

brainly.com/question/14144270

#SPJ4

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<span>It would be hotter near the Earth's equator and colder near Earth's poles</span>
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A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit
Lubov Fominskaja [6]

Answer:

58515.9 m/s

Explanation:

We are given that

d_1=4.7\times 10^{10} m

v_i=9.5\times 10^4 m/s

d_2=6\times 10^{12} m

We have to find the speed (vf).

Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.

K_i+U_i=K_f+U_f

\frac{1}{2}mv^2_i-\frac{GmM}{d_1}=\frac{1}{2}mv^2_f-\frac{GmM}{d_2}

\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2}=\frac{1}{2}v^2_f

v^2_f=2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})

v_f=\sqrt{2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})}

Using the formula

v_f=\sqrt{v^2_i+2GM(\frac{1}{d_2}-\frac{1}{d_1})}

v_f=\sqrt{(9.5\times 10^4)^2+2\times 6.7\times 10^{-11}\times 1.98\times 10^{30}(\frac{1}{6\times 10^{12}}-\frac{1}{4.7\times 10^{10})}

Where mass of sun=M=1.98\times 10^{30} kg

G=6.7\times 10^{-11}

v_f=58515.9 m/s

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Formula for kinetic energy is:
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Now we have:
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A cart was allowed to roll down a ramp from rest. It reached the bottom of the ramp with a speed of 25 cm/s. A student could con
ladessa [460]

Answer:

A student could conclude that the cart gained momentum as it rolled down.

Explanation:

If the cart was allowed to roll down the ramp from rest, it means that the initial velocity of the cart is zero (0). Also, if the final velocity of the cart became 25 cm/s, it means that the velocity of the cart increased from 0 to 25 cm/s.

Therefore, A student could conclude that the cart gained momentum as it rolled down.

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