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Romashka-Z-Leto [24]
3 years ago
11

Which element melts at room temperature?

Chemistry
2 answers:
daser333 [38]3 years ago
6 0
A melting element at room temperature consist of francium.

~Evie

just olya [345]3 years ago
4 0
Francium is an element that melts at room temperature. Francium is a highly reactive element, and only contains one valence electron, which is very ironic in my opinion. 
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Salt crystals are shaped like cubes. Salt is part of the _____. isometric crystal system monoclinic crystal system hexagonal cry
sweet [91]
Salt crystals are shaped like cubes. Salt is part of the isometric crystal system. 
6 0
3 years ago
Read 2 more answers
How many moles are in 1.20 times 10^25 atoms of phosphorus
Stels [109]

19.927 moles are in 1.20 times 10^{25} atoms of phosphorus.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 ×10^{23} of some chemical unit, be it atoms, molecules, ions, or others.

1 mole of any substance contain Avogadro's number of molecules so we can calculate the number of moles by dividing the provided number of atoms over Avogadro's number to obtain the number of moles .

Moles= \frac{Atoms}{\;Avogadro's \;number }

Moles=  1.20 X 10^{25} atoms ÷ 6.022 X 10^{23}

= 19.927

Hence, 19.927 moles are in 1.20 times 10^{25} atoms of phosphorus.

Learn more about moles here:

brainly.com/question/26416088

#SPJ1

5 0
1 year ago
The combustion of glucose (c6h12o6) with oxygen gas produces carbon dioxide and water. this process releases 2803 kj per mole of
V125BC [204]

Answer:- 335 kcal of heat energy is produced.

Solution:- The balanced equation for the combustion of glucose in presence of oxygen to give carbon dioxide and water is:

C_6H_1_2O_6+6O_2\rightarrow 6CO_2+6H_2O

From given info, 2803 kJ of heat is released bu the combustion of 1 mol of glucose. We need to calculate the energy produced when 3.00 moles of oxygen react with excess of glucose.

We could solve this using dimensional analysis as:

3.00mol O_2(\frac{1mol glucose}{6mol O_2})(\frac{2803 kJ}{1mol glucose})

= 1401.5 kJ

Now, let's convert kJ to kcal.

We know that, 1kcal = 4.184kJ

So, 1401.5kJ(\frac{1kcal}{4.184kJ})

= 335 kcal

Hence, 335 kcal of heat energy is produced by the use of 3.00 moles of oxygen gas.


8 0
3 years ago
M CALCULATOR
dolphi86 [110]
Could you post another question with a photo? I am sorry...
6 0
2 years ago
Plz help ya' girl out!<br> Label the parts of whatever that is <br> Plz giving brainliest!
Burka [1]

Answer:

BRAINLIEST PLEASE!!!

A = Smooth Endoplasmic Reticulum

B = Vacuole

C = Mitochondria (Plural)

D = Nucleolus

E = Cell Wall

Explanation:

This is obviously a plant cell. Animal cells do not have cell walls(E), and most animal cells will not have a vacuole(B). Smooth Endoplasmic Reticulum: This produces protiens (contains ribosomes) but when looked through a microscope, will appear to be smooth. The vacuole(B) is like a storage for the plant cell, and it helps support the plant cell. This is the reason why plants “droop” when you don’t water them for a long time. Mitochondia (Plural) processes nutrients for the cell. The nucleolus(D) covers the nucleus. It’s main function is to process RNA and combine it with proteins. The cell wall(E) helps support and protect the cell.

4 0
2 years ago
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