Answer:
The angle between the mirrors is 90°.
Explanation:
Given that,
Number of image = 5
Rahul kept two plane mirrors at a certain angle in front of a burning candle.
We need to find the angle between the mirrors
Using given data
When Rahul kept two plane mirrors at a certain angle in front of a burning candle then see the 5 image of candle in the mirrors.
If rahul kept two plane mirrors at a 90° then we get the 5 image of candle.
Firstly we see the two images in both mirror and now first image of first mirror is see in second mirror and second image of second mirror is see in first mirror.
So, we can say that we see the 5 image of candle in the mirrors.
Hence, The angle between the mirrors is 90°.
Answer:
A
Explanation:
The abundance of oxygen in our atmosphere and the presence of liquid water on the surface of our planet makes our "Pale Blue Dot" stand out in contrast to the other planets in the solar system — a unique and fragile home for life.
Answer:
First Kepler law states that <em><u>Each</u></em><em><u> </u></em><em><u>planet</u></em><em><u> </u></em><em><u>describes</u></em><em><u> </u></em><em><u>an</u></em><em><u> </u></em><em><u>ellipsoidal</u></em><em><u> </u></em><em><u>motion</u></em><em><u> </u></em><em><u>about</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>sun</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>its</u></em><em><u> </u></em><em><u>single</u></em><em><u> </u></em><em><u>focus</u></em><em><u>.</u></em>
Second Kepler law states that <em><u>A</u></em><em><u>n</u></em><em><u> </u></em><em><u>i</u></em><em><u>m</u></em><em><u>a</u></em><em><u>g</u></em><em><u>i</u></em><em><u>n</u></em><em><u>a</u></em><em><u>r</u></em><em><u>y</u></em><em><u> </u></em><em><u>l</u></em><em><u>i</u></em><em><u>n</u></em><em><u>e</u></em><em><u> </u></em><em><u>j</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>i</u></em><em><u>n</u></em><em><u>g</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>planet</u></em><em><u> </u></em><em><u>t</u></em><em><u>o</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>Sun</u></em><em><u> </u></em><em><u>sweeps</u></em><em><u> </u></em><em><u>out</u></em><em><u> </u></em><em><u>equal</u></em><em><u> </u></em><em><u>areas</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>equal</u></em><em><u> </u></em><em><u>time</u></em><em><u> </u></em><em><u>intervals</u></em><em><u>.</u></em>
Third Kepler law states that <em><u>The</u></em><em><u> </u></em><em><u>squares</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>period</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>revolution</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>planet</u></em><em><u> </u></em><em><u>around</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>sun</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>proportional</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>cubes</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>mean</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>between</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>planet</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>sun</u></em><em><u>.</u></em>
Weightlessness is the condition where the body has zero gravity ( its acceleration is equal to the acceleration due to gravity )

Answer:
1. 571.43m/s
2. 142.9m and 342.9m
Explanation:
1.Take the difference in time.
1.2-0.7=0.7 seconds
Take the distance between them and divide with differnce in time.
400÷0.7=571.43 seconds.
2.Take the time of the two men and divide by two.
0.5÷2= 0.25 secs
1.2÷2= 0.6 secs
multiply each with the velocity.
0.25×571.43=142.9m
0.6×571.43=342.9m
Answer:
88km E
Explanation:
25 km is added already
then if we take the formula of speed(V)
V=d/t
and rearrange it to subject d (distance)
d= V x t
we get
d= 42km/h x 1.5hrs
we get
63 km
now if we add the already travelled 25 km to this additional distance
63km + 25km = 88km
Thus the final distance traversed by the ship from its origin is
88km E
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