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son4ous [18]
3 years ago
10

Why do some compound have 1 hydrogen, some have 2 hydrogens, and some have 3 hydrogens?

Chemistry
1 answer:
Mademuasel [1]3 years ago
6 0
Because the amount of hydrogens all depends on the valence electrons
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Perform the following calculations to the correct number of significant figures.
SSSSS [86.1K]
Answer: 460.624

Explanation:
1. Multiply the numbers
(24.5260 x 2.56) + 397.84
= (62.784) + 397.84

2. Add the numbers
(62.784) + 397.84
= 460.624
4 0
2 years ago
How many hydrogen atoms are attached to each carbon adjacent to a double bond? nurition?
larisa [96]
That depends. there are 2 possible answers.
      H
C - C = C - H gives a different answer on the right than on the left.

One the left side, the second Carbon is attached to a double bond and has but one hydrogen attached to it.

The Carbon on the right of the double bond has 2
     H
C- C = C - H
            H

I'm not sure what you should put. It's one of those things that I would repeat my argument and submit it.
3 0
4 years ago
How does an object become electrically charged?will give brainliest
ICE Princess25 [194]

Answer:

It is Though the transfer of charges from one object to another, or (A).

3 0
3 years ago
Assume the pH of household bleach is 12. What is the hydronium ion concentration in household bleach? What is it hydroxide ion c
Ostrovityanka [42]

Answer:

[H3O+] = 1.0*10^-12 M

[OH-] = 0.01 M

Explanation:

We can use the following equation to find the hydronium ion concentration.  Plug in the pH and solve for H3O+.

pH = -log[H3O+]

<u>[H3O+] = 1.0*10^-12 M</u>

Now, to find the hydroxide ion concentration we will use the two following equations.

14 = pH + pOH

pOH = -log[OH-]

14 = 12 + pOH

pOH = 2

2 = -log[OH-]

<u>[OH-] = 0.01 M</u>

8 0
3 years ago
4. Al2O3 (s) + 6HCl (aq) → 2AlCl3 (aq) + 3H20(1) Find the mass of AlCl3 that is produced when 10.0 grams of Al2O3 react with 10.
slava [35]

Answer:

Are produced 12,1 g of AlCl₃ and 5,33 g of Al₂O₃ are left over

Explanation:

For the reaction:

Al₂O₃ (s) + 6 HCl (aq) → 2AlCl₃ (aq) + 3H₂0(l)

10,0g of Al₂O₃ are:

10,0g ₓ\frac{1mol}{102g} = <em>0,0980 moles</em>

And 10,0g of HCl are:

10,0 gₓ\frac{1mol}{36,5g} = <em>0,274 moles</em>

<em />

For a total reaction of 0,274 moles of HCl you need:

0,274×\frac{1molesAl_{2}O_3}{6 mole HCl} = <em>0,0457 moles of Al₂O₃</em>

Thus, limiting reactant is HCl

The grams produced of AlCl₃ are:

0,274 moles HCl ×\frac{2 moles AlCl_{3}}{6 moles HCl} × 133\frac{g}{mol} = <em>12,1 g of AlCl₃</em>

<em />

The moles of Al₂O₃ that don't react are:

0,0980 moles - 0,0457 moles =<em> </em>0,0523 moles

And its mass is:

0,0523 molesₓ\frac{102g}{1mol} = <em>5,33 g of Al₂O₃ </em>

<em />

I hope it helps!

7 0
3 years ago
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