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Jet001 [13]
1 year ago
11

Katie rolls a toy car off the end of a table.

Physics
2 answers:
harkovskaia [24]1 year ago
7 0

Answer:

The toy car will fall off Katie's hands and onto the ground .

Explanation:

This happens due to gravity.

zhenek [66]1 year ago
7 0
It will go to path c

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What stage do most stars spend the majority of their lives in?
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It a stage known as the "Main Sequence" stage. Stars achieve nuclear stability at this point and remain in this stage until the end of their lives.
Have a nice day!

8 0
3 years ago
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If the work done to stretch an ideal spring by 4.0 cm is 6.0J, what is the spring constant (force constant) of this spring?
cluponka [151]
As AL2006 correctly pointed out the formula is 1/2 kx^2.  I was thinking of force and work is the integral of force over the distance applied.  So now
W= \frac{1}{2}k x^{2}
and
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8 0
3 years ago
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A model rocket accelerates upward from the ground with a constant acceleration, reaching a height of 50 m in 8 s.What is the spe
LekaFEV [45]

Answer:

The  value is  v =  12.5 \  m/s

Explanation:

From the question we are told that

    The  height is  h  =  50 \  m

    The  time taken is  t =  8 \ s

   

From the equation of motion we have  that

 s =  ut + \frac{1}{2}  * a * t^2

Here u = 0  because the rocket started at rest

  50 =  0 + \frac{1}{2} * a  * 8^2

=>   a =  \frac{100}{64}

=>    a =  1.5625 \ m/s^2

Also from the kinematic equation we have that

    v  =  u + at

=>  v =  0 +  (8  *  1.5625)

=>   v =  12.5 \  m/s

       

5 0
3 years ago
You are observing a spacecraft moving in a circular orbit of radius 100,000 km around a distant planet. You happen to be located
Natalija [7]

To solve this problem we will apply the concepts related to centripetal acceleration, which will be the same - by balance - to the force of gravity on the body. To find this acceleration we must first find the orbital velocity through the Doppler formulas for the given periodic signals. In this way:

v_{o} = c (\frac{\lambda_{max}-\bar{\lambda}}{\bar{\lambda}}})

Here,

v_{o} =  Orbital Velocity

\lambda_{max} = Maximal Wavelength

\bar{\lambda}} = Average Wavelength

c = Speed of light

Replacing with our values we have that,

v_{o} = (3*10^5) (\frac{3.00036-3}{3})

<em>Note that the average signal is 3.000000m</em>

v_o = 36 km/s

Now using the definition about centripetal acceleration we have,

a_c = \frac{v^2}{r}

Here,

v = Orbit Velocity

r = Radius of Orbit

Replacing with our values,

a = \frac{(36km/s)^2}{100000km}

a= 0.01296km/s^2

a = 12.96m/s^2

Applying Newton's equation for acceleration due to gravity,

a =\frac{GM}{r^2}

Here,

G = Universal gravitational constant

M = Mass of the planet

r = Orbit

The acceleration due to gravity is the same as the previous centripetal acceleration by equilibrium, then rearranging to find the mass we have,

M = \frac{ar^2}{G}

M = \frac{(12.96)(100000000)^2}{ 6.67*10^{-11}}

M = 1.943028*10^{27}kg

Therefore the mass of the planet is 1.943028*10^{27}kg

7 0
3 years ago
A solid box made from a material whose density is rhoS floats with two thirds of its volume submerged in a liquid whose density
jok3333 [9.3K]

Answer:

\frac{\rho_S}{\rho_L} = \frac{2}{3}

Explanation:

density of the solid box material = \rho_s

density of the liquid material = \rho_L

Given that

solid box floats with two thirds of its volume submerged in a liquid

let V be the volume of the box

then,

V\rho_sg= \frac{2V}{3}\rho_L g

⇒\frac{\rho_S}{\rho_L} = \frac{2}{3}

so, the ratio of densities of solid and and the liquid is 2/3

7 0
3 years ago
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