Question

suppose you had a beam that is 1.51.5m in length and you place a fulcrum .25.25m from the left end of the beam (assume the beam is massless). you have a block of mass 77kg and you place it .3.3m from the right end of the beam. what is the torque on the beam?

Answer 1

The torque on the beam calculated from the principle of moments is 68 N to the right.

What is the torque on the beam?

The torque on the beam is calculated using the principle of moments.

The principle of moments states that the sum of the clockwise moments is equal to the sum of the anticlockwise moments about a fixed point for a system in equilibrium.

Moment = force * perpendicular distance from the fulcrum

Taking the left end of the beam as the anticlockwise direction ad the right end of the beam as the clockwise direction:

Anticlockwise moment = F * (0.75 - 0.25)

Where F is the balancing force

Anticlockwise moment = 0.5f

Clockwise moment = (0.77 * 9.8) * (0.75 - 0.3)

Clockwise moment = 34 J

0.5 F = 34

F = 68 N

Hence, torque is 68 N

Learn more about torque at: brainly.com/question/20691242

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