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Len [333]
1 year ago
10

Substances that move to the stronger parts of a magnetic field are termed ______ substances; the atomic feature responsible for

this property is ______ in atoms.
Physics
1 answer:
Arisa [49]1 year ago
3 0

Substances that move to the stronger parts of a magnetic field are termed paramagnetic substances; the atomic feature responsible for this property is presence of unpaired electrons in atoms.

<h3>What is a paramagnetic substance?</h3>

A paramagnetic substance is the substance that possess unpaired electrons that are heavily attracted in a magnetic field.

A magnetic field is defined as the field that exists around a magnet that produces a field of force.

Examples of paramagnetic substance include the following:

  • aluminum,
  • gold,
  • copper.
  • Chromium, and
  • Manganese.

These substances are known as paramagnetic substances because they possess a high number of unpaired electrons.

Other properties of a paramagnetic substance include the following:

  • They have a permanent dipole moment or permanent magnetic moment.
  • They are weakly magnetized in the direction of the magnetizing field.
  • They usually have constant relative permeability (μr) slightly greater than 1.

Therefore, Substances that move to the stronger parts of a magnetic field are termed paramagnetic substances; the atomic feature responsible for this property is presence of unpaired electrons in atoms.

Learn more about magnets here:

brainly.com/question/26171648

#SPJ1

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Answer: 10 s, 30 m/s , 150 m

Explanation:

Given

The speed of motorcyclist is  u_1=15\ m/s

The initial speed of a police motorcycle is u_2=0\ m/s

acceleration of police motorcycle is a=3\ m/s^2

Police will catch the motorcyclist when they traveled equal distances

distance traveled by motorcyclist in time t is

\Rightarrow s_1=15\times t

Distance traveled by Police in time t is

\Rightarrow s_2=u_2t+\frac{1}{2}at^2\\\Rightarrow s_2=0+0.5\times 3\times t^2

put s_1=s_2

\Rightarrow 15t=0.5\times 3\times t^2\\\\\Rightarrow t(1.5t-15)=0\\\\\Rightarrow t=\dfrac{15}{1.5}=10\ s

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\Rightarrow v_2=u_2+at\\\Rightarrow v_2=0+3\times 10=30\ m/s

Distance traveled by each vehicle is

\Rightarrow s_1=s_2=15\times t=15\times 10=150\ m

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