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Len [333]
1 year ago
10

Substances that move to the stronger parts of a magnetic field are termed ______ substances; the atomic feature responsible for

this property is ______ in atoms.
Physics
1 answer:
Arisa [49]1 year ago
3 0

Substances that move to the stronger parts of a magnetic field are termed paramagnetic substances; the atomic feature responsible for this property is presence of unpaired electrons in atoms.

<h3>What is a paramagnetic substance?</h3>

A paramagnetic substance is the substance that possess unpaired electrons that are heavily attracted in a magnetic field.

A magnetic field is defined as the field that exists around a magnet that produces a field of force.

Examples of paramagnetic substance include the following:

  • aluminum,
  • gold,
  • copper.
  • Chromium, and
  • Manganese.

These substances are known as paramagnetic substances because they possess a high number of unpaired electrons.

Other properties of a paramagnetic substance include the following:

  • They have a permanent dipole moment or permanent magnetic moment.
  • They are weakly magnetized in the direction of the magnetizing field.
  • They usually have constant relative permeability (μr) slightly greater than 1.

Therefore, Substances that move to the stronger parts of a magnetic field are termed paramagnetic substances; the atomic feature responsible for this property is presence of unpaired electrons in atoms.

Learn more about magnets here:

brainly.com/question/26171648

#SPJ1

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Dahasolnce [82]
<span>3.92 m/s^2 Assuming that the local gravitational acceleration is 9.8 m/s^2, then the maximum acceleration that the truck can have is the coefficient of static friction multiplied by the local gravitational acceleration, so 0.4 * 9.8 m/s^2 = 3.92 m/s^2 If you want the more complicated answer, the normal force that the crate exerts is it's mass times the local gravitational acceleration, so 20.0 kg * 9.8 m/s^2 = 196 kg*m/s^2 = 196 N Multiply by the coefficient of static friction, giving 196 N * 0.4 = 78.4 N So we need to apply 78.4 N of force to start the crate moving. Let's divide by the crate's mass 78.4 N / 20.0 kg = 78.4 kg*m/s^2 / 20.0 kg = 3.92 m/s^2 And you get the same result.</span>
6 0
3 years ago
An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temper
bixtya [17]

Answer:

a. P=18.61\ W

b. \eta_c=0.6976=69.76\%

c. \eta=0.4718=47.18\%

Explanation:

Given:

  • temperature of the hotter reservoir, T_H=1250\ K
  • temperature of the colder reservoir, T_C=378\ K
  • heat absorbed by the engine, Q_H=1.42\times 10^{5}\ J
  • heat rejected to the cold reservoir, Q_L=7.5\times 10^4\ J
  • time duration of the energy transfer, t=1\ hr=3600\ s

<u>Now the work done by the engine:</u>

Using energy conservation,

W=Q_H-Q_L

W=14.2\times 10^4-7.5\times 10^4

W=6.7\times 10^4\ J

a.

<u>Hence the power output:</u>

P=\frac{W}{t}

P=\frac{6.7\times 10^4}{3600}

P=18.61\ W

b.

\eta_c=1-\frac{T_L}{T_H}

\eta_c=1-\frac{378}{1250}

\eta_c=0.6976=69.76\%

c.

now actual efficiency:

\eta=\frac{W}{Q_H}

\eta=\frac{6.7\times 10^4}{1.42\times 10^{5}}

\eta=0.4718=47.18\%

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