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Basile [38]
3 years ago
9

To distinguish between properties of the two major types of supernovae: massive star supernovae and white dwarf supernovae. all

supernovae represent the explosions of stars, but current understanding suggests there are two basic types of supernovae: one that occurs when a massive star reaches the end of its life, and the other that occurs when a white dwarf star explodes because its mass has exceeded the white dwarf limit (also called the chandrasekhar limit) of 1.4 solar masses.
Physics
1 answer:
const2013 [10]3 years ago
3 0
<span>In my opinion, I myself believe that there are only two supernovae. The first is the white dwarf. It makes sense because if something is too big for its size, it will "explode". Just like a basketball with too much air. Massive star supernovae is like something has reached it's full potential and cannot get any bigger or better.</span>
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The energy that generates wind comes from what source?
Rudiy27

Answer:

we can say that wind energy is due to

D) Severe thunderstorms

Explanation:

As we know that wind energy is converted into kinetic energy of wind mills

This kinetic energy of wind mill is then converted into electrical energy using turbine

now we can consider here  energy conservation theory that energy is only converted from one form to other form

it neither be destroyed nor be created but it can transfer from one form to other form

So here we can say that wind energy is due to

D) Severe thunderstorms

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3 years ago
A.
Elanso [62]

Answer:

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A silver wire has a cross sectional area a = 2.0 mm2. a total of 9.4 × 1018 electrons pass through the wire in 3.0 s. the conduc
marta [7]
This problem uses the relationships among current I, current density J, and drift speed vd. We are given the total of electrons that pass through the wire in t = 3s and the area A, so we use the following equation to to find vd, from J and the known electron density n, so: 

v_{d} =  \frac{J}{n\left | q \right |}

<span>The current I is any motion of charge from one region to another, so this is given by:

</span>I = \frac{\Delta Q}{\Delta t} = \frac{9.4x1018electrons}{3s} = 3189.73(A)

The magnitude of the current density is:

J = \frac{I}{A} = \frac{3189.73}{2x10^{-6}} = 1594.86(A/m^{2})

Being:

A=2mm^{2} = 2x10^{-6}m^{2}
<span>
Finally, for the drift velocity magnitude vd, we find:

</span>v_{d} = \frac{1594.86}{5.8x1028\left |1.60x10^{-19}|\right } = 1.67x10^{18}(m/s)

Notice: The current I is very high for this wire. The given values of the variables are a little bit odd
6 0
3 years ago
How do u answer this?
gayaneshka [121]

Answer:

food

Explanation:

did you get a chance to look at the maximum number of devices allowed by

4 0
3 years ago
You have a source of energy containing 21 gj of energy at 600k how much this energy can be converted to work when rejecting heat
sweet [91]

Answer:

Available energy = 35 x 10⁶ J

Explanation:

Given:

Amount of energy (Q) = 21 gj = 21 x 10⁹ J

Temperature T1 = 600 k

Temperature T0 = 27 + 273 = 300k

Find:

Available energy

Computation:

Available energy = Q[1/T0 - 1/T1]

Available energy = 21 x 10⁹ J[1/300 - 1/600]

Available energy = 35 x 10⁶ J

4 0
3 years ago
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