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Nikitich [7]
1 year ago
5

3. Saagar gives a certain teacher some sass followed by an eye roll. Suddenly, a shoe is thrown at him.

Physics
1 answer:
joja [24]1 year ago
8 0

The average acceleration of the shoes thrown at him, a =2.775 m/s².

<h3>Equation :</h3>

To find the acceleration with given data we use this formula,

v = u + aΔt

Where,

v is final velocity

u is initial velocity

a is acceleration

Δt is time

So,

v - u = aΔt

a = v - u /Δt

a = 12km/hr - 0 / 1.2 s

a = 12km/hr / 1.2s

Changing km/hr into m/s,

1 kilometer/hour = 1000meters / 3600 seconds

We get,

12km/hr = 3.33m/s

a = 3.33 m/s / 1.2s

a = 2.775 m/s²

<h3>What is velocity ?</h3>

When an object is moving, its velocity is the rate at which its direction is changing as seen from a specific point of view and as measured by a specific unit of time. Velocity is the rate and direction of an object's movement, whereas speed is the time rate at which an object is moving along a path.

To know more about speed :

brainly.com/question/28224010

#SPJ9

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In 1970, a rocket powered car called Blue Flame achieved a maximum speed of 1.00(10 km/h (278m/s).Suppose the magnitude of the c
sammy [17]

Answer:

Distance traveled during this acceleration will be 6950 m

Explanation:

Wear have given maximum speed tat will be equal to final speed of the car        v = 278 m/sec

Constant acceleration a=5.56m/sec^2

As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec

From third equation of motion v^2=u^2+2as

Putting all values in equation

278^2=0^2+2\times 5.56\times s

s = 6950 m

So distance traveled during this acceleration will be 6950 m

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Which statement about dwarf planets is true?
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3 years ago
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When a driver presses the brake pedal, his car can stop with an acceleration of -5.4m/s^2. How far will the car travel while com
Dahasolnce [82]
Information that is given:
a = -5.4m/s^2
v0 = 25 m/s
---------------------
S = ?
Calculate the S(distance car traveled) with the formula for velocity of decelerated motion:
v^2 = v0^2 - 2aS
The velocity at the end of the motion equals zero (0) because the car stops, so v=0.
0 = v0^2 - 2aS
v0^2 = 2aS
S = v0^2/2a
S = (25 m/s)^2/(2×5.4 m/s^2)
S = (25 m/s)^2/(10.8 m/s^2)
S = (625 m^2/s^2)/(10.8 m/s^2)
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3 years ago
Define alpha and beta​
elena55 [62]

alpha is the excess return on an investment after adjusting for market related volatility and random fluctuations.

beta is a measure of volatility relative to a benchmark ,such as the S&P 500.

Explanation:

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3 years ago
Determine a formula for the acceleration of the system in terms of mA, mB, θ, and g. Ignore the mass of the cord and pulley. Exp
jekas [21]

Answer:

a=\frac{mBg-mAgSin\theta}{mA+mB}

Explanation:

Given two mass on an incline code mA and mB and an angle of inclination \theta. g. Assume that mA is the weight being pulled up and mB the hanging weight.

-The equations of motion from Newton's Second Law are:

mBg-T=mBa where a is the acceleration.

#Substituting for T (tension) gives:

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#and solving for a:

a=\frac{mBg-mAgSin\theta}{mA+mB} which is the system's acceleration.

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