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1 year ago

3. Saagar gives a certain teacher some sass followed by an eye roll. Suddenly, a shoe is thrown at him.

Physics

1 answer:

joja [24]1 year ago

8 0

The average acceleration of the shoes thrown at him, a =2.775 m/s².

<h3>Equation :</h3>

To find the acceleration with given data we use this formula,

v = u + aΔt

Where,

v is final velocity

u is initial velocity

a is acceleration

Δt is time

So,

v - u = aΔt

a = v - u /Δt

a = 12km/hr - 0 / 1.2 s

a = 12km/hr / 1.2s

Changing km/hr into m/s,

1 kilometer/hour = 1000meters / 3600 seconds

We get,

12km/hr = 3.33m/s

a = 3.33 m/s / 1.2s

a = 2.775 m/s²

<h3>What is velocity ?</h3>

When an object is moving, its velocity is the rate at which its direction is changing as seen from a specific point of view and as measured by a specific unit of time. Velocity is the rate and direction of an object's movement, whereas speed is the time rate at which an object is moving along a path.

To know more about speed :

brainly.com/question/28224010

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A quick USB charger claims its output current is 1.97Amp. We know that the standard USB output voltage is 5V. What is the output

Arte-miy333 [17]

Answer:

Output power of the charger is 9.85 watts.

Explanation:

It is given that,

Output current of the USB charger, I = 1.97 A

The standard USB output voltage, V = 5 V

We need to find the output power of the charger. It can be determined using the following formula as :

P = V × I

$P=5\ V\times 1.97\ A$

P = 9.85 watts

The output power of the charger is 9.85 watts. Hence, this is the required solution.

3 0

3 years ago

Amy is standing still on the ground; Bill is riding his bicycle at 5 m/s eastward; and Carlos is driving his car at 15 m/s westw

Solnce55 [7]

Answer:

20 m/s westward

Explanation:

Taking eastward as positive direction, we have:

$v_B = +5 m/s$ is the velocity of Bill with respect to Amy (which is stationary)

$v_C = -15 m/s$ is the velocity of Carlos with respect to Amy

Bill is moving 5 m/s eastward compared to Amy at rest, so the velocity of Bill's reference frame is

$v_B = +5 m/s$

Therefore, Carlos velocity in Bill's reference frame will be

$v_C' = v_C - v_B = -15 m/s - (+5 m/s) = -20 m/s$

and the direction will be westward (negative sign).

3 0

3 years ago

The note created by a flute will increase the speed of sound increases. When a marching band goes outside on a cold day, what wo

alexgriva [62]

A).

It would decrease because the speed of sound and temperature are proportional.

4 0

3 years ago

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Main method of energy transfer

tatyana61 [14]

Answer:

Electrification induction

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3 years ago

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Block B is attached to a massless string of length L = 1 m and is free to rotate as a pendulum. The speed of block A after the c

Amanda [17]

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The minimum velocity of A is $v_A= 4m/s$

Explanation:

From the question we are told that

The length of the string is $L = 1m$

The initial speed of block A is $u_A$

The final speed of block A is $v_A = \frac{1}{2}u_A$

The initial speed of block B is $u_B = 0$

The mass of block A is $m_A = 7kg$ gh

The mass of block B is $m_B = 2 kg$

According to the principle of conservation of momentum

$m_A u_A + m_B u_B = m_Bv_B + m_A \frac{u_A}{2}$

Since block B at initial is at rest

$m_A u_A = m_Bv_B + m_A \frac{u_A}{2}$

$m_A u_A - m_A \frac{u_A}{2} = m_Bv_B$

$m_A \frac{u_A}{2} = m_Bv_B$

making $v_B$ the subject of the formula

$v_B =m_A \frac{u_A}{2 m_B}$

Substituting values

$v_B =\frac{7 u_A}{4}$

This $v__B$ is the velocity at bottom of the vertical circle just at the collision with mass A

Assuming that block B is swing through the vertical circle(shown on the second uploaded image ) with an angular velocity of $v__B'$ at the top of the vertical circle

The angular centripetal acceleration would be mathematically represented

$a= \frac{v^2_{B}'}{L}$

Note that this acceleration would be toward the center of the circle

Now the forces acting at the top of the circle can be represented mathematically as

$T + mg = m \frac{v^2_{B}'}{L}$

Where T is the tension on the string

According to the law of energy conservation

The energy at bottom of the vertical circle = The energy at the top of

the vertical circle

This can be mathematically represented as

$\frac{1}{2} m(v_B)^2 = \frac{1}{2} mv^2_B' + mg 2L$

From above

$(T + mg) L = m v^2_{B}'$

Substitute this into above equation

$\frac{1}{2} m(\frac{7 v_A}{4} )^2 = \frac{1}{2} (T + mg) L + mg 2L$

$\frac{49 mv_A^2}{16} = \frac{1}{2} (T + mg) L + mg 2L$

$\frac{49 mv_A^2}{16} = T + 5mgL$

The value of velocity of block A needed to cause B be to swing through a complete vertical circle is would be minimum when tension on the string due to the weight of B is zero

This is mathematically represented as

$\frac{49 mv_A^2}{16} = 5mgL$

making $v_A$ the subject

$v_A = \sqrt{\frac{80mgL}{49m} }$

substituting values

$v_A = \sqrt{\frac{80* 9.8 *1}{49} }$

$v_A= 4m/s$

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3 years ago