Take the missile's starting position to be the origin. Assuming the angles given are taken to be counterclockwise from the positive horizontal axis, the missile has position vector with components
The missile's final position after 9.20 s has to be a vector whose distance from the origin is 19,500 m and situated 32.0 deg relative the positive horizontal axis. This means the final position should have components
So we have enough information to solve for the components of the acceleration vector, 
and 
:
The acceleration vector then has direction 
where
Answer : The final pressure in the two containers is, 2.62 atm
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
Thus, the expression for final pressure in the two containers will be:
where,
= pressure of N₂ gas = 4.45 atm
= pressure of Ar gas = 2.75 atm
= volume of N₂ gas = 3.00 L
= volume of Ar gas = 2.00 L
P = final pressure of gas = ?
V = final volume of gas = (4.45 + 2.75) L = 7.2 L
Now put all the given values in the above equation, we get:
Thus, the final pressure in the two containers is, 2.62 atm
Answer:
The hollow cylinder rolled up the inclined plane by 1.91 m
Explanation:
From the principle of conservation of mechanical energy, total kinetic energy = total potential energy
The total energy at the bottom of the inclined plane = total energy at the top of the inclined plane.
moment of inertia, I, of a hollow cylinder = ¹/₂mr²
substitute for I in the equation above;
given;
v₁ = 5.0 m/s
vf = 0
g = 9.8 m/s²
Therefore, the hollow cylinder rolled up the inclined plane by 1.91 m
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