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Naily [24]
1 year ago
15

Iodine and tellurium were swapped by Mendeleev in the Periodic Table so that they were not in order of atomic weight. State the

type of atom that gives an explanation as to why order based on atomic mass is not always correct.
Chemistry
2 answers:
zmey [24]1 year ago
7 0

The example of Iodine and tellurium where iodine which had lesser atomic mass was placed before tellurium proved that order of the Periodic table based on atomic mass was not always correct.

<h3>Why did Mendeleev swap Iodine and tellurium in his Periodic Table so that they were not in order of atomic weight?</h3>

The periodic table as designed by Mendeleev was arranged such that the elements were arranged in order of increasing atomic mass.

However, in this case of tellurium and iodine, Mendeleev placed tellurium before iodine even though it had a greater atomic mass than iodine. This was because Mendeleev observed that elements with similar chemical properties were occurring in a regular pattern in the periodic table and iodine has similar chemical properties to bromine and chlorine before it.

Therefore, the case of Iodine and tellurium proved that arranging elements in the periodic table in order of increasing atomic mass was not always correct.

Learn more about Mendeleev periodic table at: brainly.com/question/2165846

#SPJ1

k0ka [10]1 year ago
5 0

Answer:

literally all you have to write to get the mark is the word isotopes

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When 2.0 mol of methanol is dissolved in 45 grams of water, what is the mole fraction of methanol
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The mole fraction of methanol in the mixture is 0.444

We'll begin by calculating the number of mole of water.

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Mole = mass / molar mass

Mole of water = 45 / 18

Mole of water = 2.5 moles

Finally, we shall determine the mole fraction of methanol.

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Mole fraction of methanol =?

Mole fraction = mole / total mole

Mole fraction of methanol = 2 / 4.5

Mole fraction of methanol = 0.444

Thus, the mole fraction of methanol is 0.444

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3 years ago
What equation represents the pressure of a gas under ideal conditions?
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4 years ago
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0.350 mol of a solid was dissolved in 260 mL of water at 21.2 oC. After the solid had fully dissolved, the final temperature of
Fittoniya [83]

Answer: Heat of the solution  = mass water × specific heat water × change in temperature

mass water = 260ml (1.00g/ml ) = 260g

specific heat of water = c(water) = 4.184J/ g°C

Heat change of water = final temperature - initial temperature

                                       = 26.5 - 21.2

                                        = 5.3 °C

H = 260 g ( 4.184J/g°C ) (5.3°C) = 5765J

Molar heat = \frac{5765J}{0.350mol}

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Explanation: finding molar heat requires first to look at  specific heat of water and the change of water temperature

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3 years ago
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C₀=2 mol/l
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v₁=100.0 ml = 0.1 l

c₁v₁=c₀v₀

v₀=c₁v₁/c₀
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v₀=0.1*0.400/2=0.02 l = 20 ml
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It is necessary to mix 20 ml of the feed solution and 80 ml of water.

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