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Naily [24]
10 months ago
15

Iodine and tellurium were swapped by Mendeleev in the Periodic Table so that they were not in order of atomic weight. State the

type of atom that gives an explanation as to why order based on atomic mass is not always correct.
Chemistry
2 answers:
zmey [24]10 months ago
7 0

The example of Iodine and tellurium where iodine which had lesser atomic mass was placed before tellurium proved that order of the Periodic table based on atomic mass was not always correct.

<h3>Why did Mendeleev swap Iodine and tellurium in his Periodic Table so that they were not in order of atomic weight?</h3>

The periodic table as designed by Mendeleev was arranged such that the elements were arranged in order of increasing atomic mass.

However, in this case of tellurium and iodine, Mendeleev placed tellurium before iodine even though it had a greater atomic mass than iodine. This was because Mendeleev observed that elements with similar chemical properties were occurring in a regular pattern in the periodic table and iodine has similar chemical properties to bromine and chlorine before it.

Therefore, the case of Iodine and tellurium proved that arranging elements in the periodic table in order of increasing atomic mass was not always correct.

Learn more about Mendeleev periodic table at: brainly.com/question/2165846

#SPJ1

k0ka [10]10 months ago
5 0

Answer:

literally all you have to write to get the mark is the word isotopes

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(a) Calculate the energy released by the alpha decay of 222 86Rn.
Alinara [238K]

Answer:

a). The energy released by the alpha decay of 222 Rn is to 218 Po :

= 5.596 MeV

b).The energy of the alpha particle is 5.5 MeV

c) The recoil energy of Po = 0.096 MeV

Explanation:

The equation for the alpha decay of Rn to Polonium is:

_{86}^{222}\textrm{Rn}\rightarrow _{2}^{4}\textrm{He}+_{84}^{218}\textrm{Po}

The energy of the decay process can be calculated using:

\Delta E=\Delta mc^{2}

\Delta m = Change in the mass

Mass of Po = 218.008965 u

Mass of He = 4.002603 u

Mass of Rn = 222.017576 u

\Delta m = mass of Po + mass of He - mass of Rn

=  4.002603 + 218.008965-222.017576  

= - 0.006008

\Delta E=m(931.5MeV)

\Delta E=-0.006008\times 931.5MeV

= -5.596 MeV

<u><em>The negative sign means energy is released during the process.</em></u>

b) The energy of the alpha particle is :

\frac{Po\ mass }{Rn\ mass}\times E

\frac{218.0089}{222.0175}\times \Delta E

\frac{218.0089}{222.0175}\times 5.596

= 5.494 MeV

= 5.5 MeV

c).

Recoil energy: When the parent nucleus is at rest before the decay then , there must be the some recoil of daughter nucleus to conserve the momentum.This is termed as recoil energy.

<u><em>The energy of the recoil polonium atom :</em></u>

The formula for recoil energy is :

<em>The total energy - the kinetic energy</em>

<em>= 5.596 - 5.5 </em>

<em>= 0.096 MeV</em>

7 0
3 years ago
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