Question

The sheet of gold foil Rutherford used was 304 mm wide and 0.016 mm thick. What maximum length of gold foil could be made from 1.10 x 103 g of gold?

Answer 1

The maximum length of gold foil could be 1171.7 cm made from 1.10 x 10³ g of gold.

What is the density?

The density of an object can be described as the mass per unit volume. The average density is equal to the total mass divided by its total volume.

The mathematical formula of the density of the material can be expressed as follows:

Density = Mass/Volume

The density of a substance is an intrinsic property as it doesn't depend on its size and the S.I. unit of the density is Kg/m³.

Given the width of the gold foil, w = 304 mm = 30.4 cm

The height or thickness of the foil, h = 0.016 mm = 0.0016 cm

The density of the gold foil, d = 19.3 g/cm³

The mass of the gold given, m = 1100 g

The volume of the foil = m/d = 1100/ 19.3 = 56.99 g/cm³

As we know that the volume of  gold foil , V = l × w × h

l = V/(w × h)

l = 56.99/(30.4 × 0.0016)

l =1171.7 cm

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