From the average speed you can fix an equation:
Average speed = distance / time
You know the average speed = 65.1 kg / h, then
65.1 = distance / total time,
where total time is the time traveling plus 22.0 minutes
Call t the time treavelling and pass 22 minutes to hours:
65.1 = distance / [t + 22/60] ==> distance = [t + 22/60]*65.1
From the constant speed, you can fix a second equation
Constant speed = distance / time traveling
94.5 = distance / t ==> distance = 94.5 * t
The distance is the same in both equations, then you have:
[t +22/60] * 65.1 = 94.5 t
Now you can solve for t.
65.1t + 22*65.1/60 = 94.5t
94.5t - 65.1t = 22*65.1/60
29.4t = 23.87
t = 23.87 / 29.4
t = 0.812 hours
distance = 94.5 km/h * 0.812 h = 76.7 km
Answers: 1) 0.81 hours, 2) 76.7 km
With the help of a transformer input voltage is transformed into an output voltage
<h3>What is induced voltage?</h3>
Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.
In this case, a magnet is pushed in and out of a wire coil attached to a high-resistance voltmeter.
Typically, a transformer's primary winding is attached to the input voltage source and changes electrical power into a magnetic field.
The secondary winding's role is to turn this alternating magnetic field into electricity, generating the necessary output voltage.
Hence with the help of a transformer input voltage is transformed into an output voltage.
To learn more about the induced voltage refer to the link;
brainly.com/question/19482771
#SPJ1
Answer:
The maximum potential difference is 186.02 x 10¹⁵ V
Explanation:
formula for calculating maximum potential difference
![V = \frac{2K_e \lambda}{k}ln(\frac{b}{a})](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B2K_e%20%5Clambda%7D%7Bk%7Dln%28%5Cfrac%7Bb%7D%7Ba%7D%29)
where;
Ke is coulomb's constant = 8.99 x 10⁹ Nm²/c²
k is the dielectric constant = 2.3
b is the outer radius of the conductor = 3 mm
a is the inner radius of the conductor = 0.8 mm
λ is the linear charge density = 18 x 10⁶ V/m
Substitute in these values in the above equation;
![V = \frac{2K_e \lambda}{k}ln(\frac{b}{a}) = \frac{2*8.99*10^9*18*10^6 }{2.3}ln(\frac{3}{0.8}) =140.71 *10^{15} *1.322 \\\\V= 186.02 *10^{15} \ V](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B2K_e%20%5Clambda%7D%7Bk%7Dln%28%5Cfrac%7Bb%7D%7Ba%7D%29%20%3D%20%20%5Cfrac%7B2%2A8.99%2A10%5E9%2A18%2A10%5E6%20%7D%7B2.3%7Dln%28%5Cfrac%7B3%7D%7B0.8%7D%29%20%3D140.71%20%2A10%5E%7B15%7D%20%2A1.322%20%5C%5C%5C%5CV%3D%20186.02%20%2A10%5E%7B15%7D%20%5C%20V)
Therefore, the maximum potential difference this cable can withstand is 186.02 x 10¹⁵ V
Answer:
The ball will have a kinetic energy of 0.615 Joules.
Explanation:
Use the kinetic energy formula
![E_k = \frac{1}{2}mv^2 = \frac{1}{2}0.032kg\cdot 6.2^2 \frac{m^2}{s^2}= 0.615J](https://tex.z-dn.net/?f=E_k%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%3D%20%5Cfrac%7B1%7D%7B2%7D0.032kg%5Ccdot%206.2%5E2%20%5Cfrac%7Bm%5E2%7D%7Bs%5E2%7D%3D%200.615J)
The kinetic energy at the moment of leaving the hand will be 0.615 Joules. (From there on, as it ball is traveling upwards, this energy will be gradually traded off with potential energy until the ball's velocity becomes zero at the apex of the flight)
Answer:
option (B)
Explanation:
Intensity of unpolarised light, I = 25 W/m^2
When it passes from first polarisr, the intensity of light becomes
![I'=\frac{I_{0}}{2}=\frac{25}{2}=12.5 W/m^{2}](https://tex.z-dn.net/?f=I%27%3D%5Cfrac%7BI_%7B0%7D%7D%7B2%7D%3D%5Cfrac%7B25%7D%7B2%7D%3D12.5%20W%2Fm%5E%7B2%7D)
Let the intensity of light as it passes from second polariser is I''.
According to the law of Malus
![I'' = I' Cos^{2}\theta](https://tex.z-dn.net/?f=I%27%27%20%3D%20I%27%20Cos%5E%7B2%7D%5Ctheta)
Where, θ be the angle between the axis first polariser and the second polariser.
![I'' = 12.5\times Cos^{2}15](https://tex.z-dn.net/?f=I%27%27%20%3D%2012.5%5Ctimes%20Cos%5E%7B2%7D15)
I'' = 11.66 W/m^2
I'' = 11.7 W/m^2