Question

determine the magnitude of the flux in kg/s (no sign, just the magnitude) of air through the surface s. the density of air is 1.2 kg/m3. the velocity of the air is

Answer 1

the velocity of the air is94.25V kg/s

Calculation :

Assuming velocity of air through spherical shell = V m/s

then flux = ρ *π *$a^{2}$*V kg/s

=1.2 *π *$5^{2}$*V  = 94.25V kg/s

Rate of change of distance. Rate of change of displacement. The velocity of a moving object can never be negative.

Velocity is the directional velocity of a moving object as an indicator of the observed rate of change of position from a given reference frame.

Velocity (v) is a vector quantity that measures displacement (or change in position, Δs) versus change in time (Δt), given by the formula v = Δs/Δt.

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Answer 2

The correct answer is 94.25 kg/s

Flux can be stated as the rate of flow of a fluid, radiant energy, or particles across a given area.

The magnetic flux is the magnetic lines present in among two magnets or solenoid is mutual flux.

Velocity is the count of difference in displacement in a given time and it is a vector quantity which has both magnitude and direction.

The mass of a sample of a chemical compound divided by the quantity, or number of moles in the sample, measured in moles, is known as the molar mass of that compound.

Given

density = 1.2 kg/m³

The velocity of the air is 94.25V kg/s

Assuming velocity of air through spherical shell = V m/s

Then flux = ρ *π * a² * V kg/s = 94.25V kg/s

Therefore, the velocity given will be 94.25V kg/s

To know more about velocity, refer: brainly.com/question/28965269

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