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Reil [10]
1 year ago
13

a negatively charged electroscope has separated leaves. (a) suppose you bring a negatively charged rod close to the top of the e

lectroscope, but not touching. how will the leaves respond? (b) how will the leaves respond if you bring a positively charged rod close to the top of the electroscope, but not touching?
Physics
1 answer:
Ganezh [65]1 year ago
3 0

The leaves of a negatively charged electroscope will move apart if a positively charged rod is brought close to the top of the electroscope, but not touching it.

What is an electroscope?

An early scientific tool used to find an electrical charge on a body is called an electroscope. The movement of a test object caused by the Coulomb electrostatic force is used to detect charge. An object's charge is inversely proportional to its voltage.

part a) leaves will repel. leaves will move further apart.

part b)  all the negative moves to the top to get closer to the positive leaves go back together as an excess negative move to the top.  leaves separate less.

To learn more about the electroscope the link is given below:
brainly.com/question/16183122?
#SPJ4

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A phonograph turntable rotating at 33 1 3 rev/min slows down and stops in 1.98 min. (Assume the turntable initially rotates in t
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Explanation:

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3 years ago
When a .22-caliber rifle is fired, the expanding gas from the burning gunpowder creates a pressure behind the bullet. This press
mario62 [17]

Answer:

1.18454\times 10^{-19}\ Pa

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

m = Mass of bullet = 2.6\times 10^{23}\ kg

r = Radius of barrel = 2.8\times 10^{23}\ m

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{370^2-0^2}{2\times 0.61}\\\Rightarrow a=112213.11475\ m/s^2

Pressure is given by

P=\dfrac{F}{A}\\\Rightarrow P=\dfrac{ma}{\pi r^2}\\\Rightarrow P=\dfrac{2.6\times 10^{23}\times 112213.11475}{\pi (2.8\times 10^{23})^2}\\\Rightarrow P=1.18454\times 10^{-19}\ Pa

The pressure of the expanding gas is 1.18454\times 10^{-19}\ Pa

7 0
3 years ago
How fast would you have to jump off the ground in order to jump at least 10 meters in the air?
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Answer:

30.5

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4 years ago
Que fuerza se obtendrá en el émbolo mayor de una prensa hidraúlica cuya área es de 167 cm2, cuando el émbolo menor de área igual
stiv31 [10]

Responder:

<h2>5.368N, </h2>

Explicación:

Según el principio pascal, establece que la presión aplicada en un punto sobre un líquido en un recipiente cerrado es igual a igual a la presión en cualquier otro punto del líquido.

Matemáticamente Presión ejercida por el pistón más pequeño = Presión ejercida por el pistón más grande.

La presión es la relación entre la fuerza y ​​su área de sección transversal.

P = Fuerza / Área de sección transversal

Sea P1 la presión sobre el pistón más pequeño y P2 la presión ejercida por el pistón más grande.

Como P1 = P2 entonces;

F1 / A1 = F2 / A2

Dado F1 = 450N, A1 = 14 cm², A2 = 167 cm² y F2 =?

Sustituyendo el valor conocido en la fórmula para obtener el requerido, tenemos;

\frac{450}{14} = \frac{F2}{167}\\  \\Cross\ multiplying\\\\14*F_2 = 450*167\\\\14F_2 = 75,150\\\\F_2 = \frac{75,150}{14} \\\\F_2 = 5,367.9N

F_2 \approx 5, 368N

Por lo tanto, la fuerza que se obtendrá en el pistón más grande de una prensa hidráulica cuya área es de 167 cm² es aproximadamente 5,368N,

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it become easier to carry a load in a wheel barrow when the load is shift towards its wheel give reason​
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