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svetoff [14.1K]
2 years ago
5

A disk-shaped space station 125 m in diameter spins at a constant angular velocity. If the acceleration of a point on the rim of

the disk is to be equal to "g", how long does it take for the station to make one revolution?
Physics
1 answer:
dedylja [7]2 years ago
5 0

Answer:

  t = 22.44 s

Explanation:

The acceleration of the station is centripetal which has the formula

         a = v² / r

linear and angular velocity are related

         v = w² r

as they indicate that the acceleration is equal to the acceleration of gravity

         g = w² r

         w = \sqrt{  \frac{g}{r} }

         

let's calculate

         w = \sqrt{ \frac{9.8}{ 125} }

         w = 0.28 rad / s

to calculate the time use us

          w = θ / t

in a complete revolution θ = 2pi

          t = θ / w

let's calculate

          t = 2π / 0, 28

          t = 22.44 s

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Answer:

The height of the pyramid is approximately 104 Ft. See the graphic attached.

Explanation:

First, you have to plot to realize that you have two rectangle triangles, formed by the different elevation points of view. From there you can have a system of two equations, with two unknown values.

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Matching (1) and (2)

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Calculate the height from from which a body is released from rest if its velocity just before hitting the ground is30m\s
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=  > 20h = 900

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