A disk-shaped space station 125 m in diameter spins at a constant angular velocity. If the acceleration of a point on the rim of
1 answer:
Answer:
t = 22.44 s
Explanation:
The acceleration of the station is centripetal which has the formula
a = v² / r
linear and angular velocity are related
v = w² r
as they indicate that the acceleration is equal to the acceleration of gravity
g = w² r
w =
let's calculate
w =
w = 0.28 rad / s
to calculate the time use us
w = θ / t
in a complete revolution θ = 2pi
t = θ / w
let's calculate
t = 2π / 0, 28
t = 22.44 s
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Answer:
a) Fg = -27.4 N
b) Fnet = 5.2 N
c) a = 1.9 m/s2
Explanation:
a)
- There are two forces acting on the ball, one directed upward (assuming this direction as positive, along the y-axis) which is the tension on the string (lifting force), and another aimed downward, which is the attractive force due to gravity.
- Applying the Newton's Universal Law of Gravitation to a mass close to the surface of the Earth (in this case the ball), we can take the acceleration due to gravity like a constant, that we call by convention g, equal to -9.8 m/s2.
- So, we can write the following expression for Fg:
b)
- The net force on the ball, will be just the difference between the lifting force (32.6 N) and the force due to gravity, Fg:
c)
- According Newton's 2nd Law, the acceleration caused by a net force on a point mass (we can take the ball as one) is given by the following expression: