A disk-shaped space station 125 m in diameter spins at a constant angular velocity. If the acceleration of a point on the rim of
1 answer:
Answer:
t = 22.44 s
Explanation:
The acceleration of the station is centripetal which has the formula
a = v² / r
linear and angular velocity are related
v = w² r
as they indicate that the acceleration is equal to the acceleration of gravity
g = w² r
w =
let's calculate
w =
w = 0.28 rad / s
to calculate the time use us
w = θ / t
in a complete revolution θ = 2pi
t = θ / w
let's calculate
t = 2π / 0, 28
t = 22.44 s
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Answer:
f.The period is independent of the suspended mass.
Explanation:
The period of a pendulum is given by
where
L is the length of the pendulum
g is the acceleration due to gravity
From the formula, we see that:
1) the period of the pendulum depends only on its length, L, and it is proportional to the square root of the length
2) the period does not depend neither on the mass of the pendulum, nor on its amplitude of oscillation
So, the only correct statements are
f.The period is independent of the suspended mass.
Note: statement "e.The period is proportional to the length of the wire" is also wrong, because the period is NOT proportional to the length of the wire, but it is proportional to the square root of it.