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Nuetrik [128]
3 years ago
14

A unit for measuring work is called the _____. horsepower effort time foot-pound

Chemistry
1 answer:
Effectus [21]3 years ago
4 0

Answer:

A unit for measuring work is called the foot-pound

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What is the pH of a 3.40 mM of acetic acid, 500 mL in which 50 mL of 1.00 M NaOAc has been added? Ka HOAc is 1.8 x 10-5? What pe
Deffense [45]

Answer:

a) pH = 4.213

b) % dis = 2 %

Explanation:

Ch3COONa → CH3COO- + Na+

CH3COOH ↔ CH3COO- + H3O+

∴ Ka = 1.8 E-5 = ([ CH3COO- ] * [ H3O+ ]) / [ CH3COOH ]

mass balance:

⇒ <em>C</em> CH3COOH + <em>C</em> CH3COONa = [ CH3COOH ] + [ CH3COO- ]

<em>∴ C </em>CH3COOH = 3.40 mM = 3.4 mmol/mL * ( mol/1000mmol)*(1000mL/L)

∴ <em>C</em> CH3COONa = 1.00 M = 1.00 mol/L = 1.00 mmol/mL

⇒ [ CH3COOH ] = 4.4 - [ CH3COO- ]

charge balance:

⇒ [ H3O+ ] + [ Na+ ] = [ CH3COO- ] + [ OH- ]....is negligible [ OH-], comes from water

⇒ [ CH3COO- ] = [ H3O+ ] + 1.00

⇒ Ka = (( [ H3O+ ] + 1 )* [ H3O+ ]) / ( 3.4 - [ H3O+])) = 1.8 E-5

⇒ [ H3O+ ]² + [ H3O+ ] = 6.12 E-5 - 1.8 E-5 [ H3O+ ]

⇒ [ H3O+ ]² + [ H3O+ ] - 6.12 E-5 = 0

⇒  [ H3O+ ] = 6.12 E-5 M

⇒ pH = - Log [ H3O+ ] = 4.213

b) (% dis)* mol acid = <em>C</em> CH3COOH = 3.4

∴ mol CH3COOH = 500*3.4 = 1700 mmol = 1.7 mol

⇒ % dis = 3.4 / 1.7 = 2 %

7 0
3 years ago
Which of the following radiations consists of a helium nucleus emitted by some radioactive substances? Alpha radiation Beta radi
erica [24]

Answer: Alpha radiation

Explanation: Alpha decay : When a larger radioactive nuclei decays into smaller nuclei by releasing alpha radiation, the mass number and atomic number is reduced by 4 and 2 units respectively.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\textrm{He}


Beta decay : When a larger radioactive nuclei decays into smaller nuclei by releasing beta radiation, the atomic number is increased by 1 unit.


_Z^A\textrm{X}\rightarrow _{Z+1}^{A}Y+_{-1}^0e


Gamma decay : When a larger radioactive nuclei decays into smaller nuclei by releasing gamma radiation, the mass number remains same.

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

5 0
3 years ago
How to calculate from moles to grams?<br> 4.0 moles of Cu(CN)2
andreyandreev [35.5K]

Answer: The mass of given amount of copper (II) cyanide is 462.4 g

Explanation:

To calculate the number of moles, we use the equation:

We are given:

Moles of copper (II) cyanide = 4 moles

Molar mass of copper (II) cyanide = 115.6 g/mol

Putting values in above equation, we get:

Hence, the mass of given amount of copper (II) cyanide is 462.4 g

3 0
3 years ago
Which best describes how a fetus exchanges gases while in the womb?
vagabundo [1.1K]

Answer:

C. Gas exchange occurs through the placenta.

Explanation:

The fetus is a developing baby in the womb or uterus. The fetus is incapable of performing certain life processes itself and hence, depends on the mother to do them. One of these processes is GAS EXCHANGE. Gas exchange occurs in the fetus via a structure called PLACENTA.

Placenta is a structure that forms in the uterus during pregnancy. It helps the developing fetus supply oxygen and nutrients from the mother and also remove wastes from the fetus back to the mother. The oxygen is taken into the fetus via the PLACENTA while the carbon dioxide (waste product of respiration) is removed via the PLACENTA. Hence, Gas exchange occurs through the placenta.

5 0
3 years ago
How many liters of water must be added to 0.291 g of NaCl to create a salt water solution that has a concentration of 2.41 g/L?
dmitriy555 [2]
C=2.41 g/L
m(NaCl)=0.291 g

c=m(NaCl)/v

v=m(NaCl)/c

v=0.291/2.41= 0.1207 L = 120.7 mL
4 0
3 years ago
Read 2 more answers
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