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Zielflug [23.3K]
3 years ago
14

PLEASE ANSWER ASAP:!!!!What characteristics of water make it essential for life and a useful chemical in the formation of soluti

ons?
Chemistry
1 answer:
Sliva [168]3 years ago
8 0
Special properties of water are its high heat capacity and heat of vaporization, its ability to dissolve polar molecules, its cohesive and adhesive properties, and its dissociation into ions that leads to generating pH. Understanding these characteristics of water helps to elucidate its importance in maintaining life.
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Which statement does NOT apply to Alkenes?
nikdorinn [45]

Answer:

They are more stable than alkanes

Explanation:

  • <em><u>Alkenes</u></em><em><u> are a type of unsaturated hydrocarbons </u></em>which means they have a<u> double bond</u> in their structure, or lack maximum number of hydrogen atoms on each carbon.
  • Alkenes have a general formula of CnH2n. They are called <u>unsaturated hydrocarbons</u> since they have a double bond. They are therefore less stable compared to alkanes and also are readily reactive.
6 0
4 years ago
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What type of bond occurs between tow nonmetals.
Aleksandr-060686 [28]

Answer:

covalent bonds............

6 0
3 years ago
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As two chlorine atoms combine to form a molecule, energy is
raketka [301]
B. released, forming bonds usually releases energy.
6 0
3 years ago
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If the atomic number of an element is 16, then it has 16 electrons.<br> True<br> False
Aleks04 [339]
True hope this helped u out cuh
4 0
3 years ago
Problem Page Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.2 g o
stich3 [128]

Answer: 0.0 grams

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of butane

\text{Number of moles}=\frac{5.2g}{58.12g/mol}=0.09moles

b) moles of oxygen

\text{Number of moles}=\frac{32.6g}{32g/mol}=1.02moles

2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O

According to stoichiometry :

2 moles of butane require 13 moles of O_2

Thus 0.09 moles of butane will require =\frac{13}{2}\times 0.09=0.585moles  of O_2

Butane is the limiting reagent as it limits the formation of product and oxygen is present in excess as (1.02-0.585)=0.435 moles will be left.

Thus all the butane will be consumed and 0.0 grams of butane will be left.

7 0
3 years ago
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