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Lubov Fominskaja [6]
1 year ago
7

The _______ atom in a water molecule points toward the sodium ion because its partial _______ charge is attracted to the sodium

ion's ______ charge. This is called _______.
Chemistry
1 answer:
makvit [3.9K]1 year ago
8 0

Answer:

Below

Explanation:

Oxygen     negative   positive    hydration

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I really need help, I don’t know what to do on this
Shtirlitz [24]

Answer:

A: dependent variable

B: experimental group

C: independent variable

D: control variables

E: control group

Explanation:

7 0
3 years ago
If the density of a liquid 102g/cm^3, how many milligrams will be in 63 mL of that liquid?
Ede4ka [16]

Answer:

<h2>6426000 mg</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question

63 mL = 63 cm³

We have

mass = 102 × 63 = 6426

But 1 g = 1000 mg

6426 g = 6426000 mg

We have the final answer as

<h3>6,426,000 mg</h3>

Hope this helps you

6 0
2 years ago
Which statement accurately describes how electrical power and voltage are
neonofarm [45]

Answer: B

Explanation:

According to Ohm's Law, the answer is B.

Ohm's Law states that power is equal to volume x current.

If volume x current equals power, that means they are both 50% of power.

Ohm's Law:

power = voltage x current

current = voltage x power

voltage = power x current

I hope this answer helped.

7 0
3 years ago
Read 2 more answers
Xavier and Ashaunda were at the beach on a nice warm and sunny weekend. They watched as puffy
ale4655 [162]

Answer:

Condensation

Explanation:

During condensation the water vapor in the air converts to liquid, this forms clouds.

You can also refer to the attached image for more validation.

4 0
2 years ago
What is the final temperature of the solution formed when 1.52 g of NaOH is added to 35.5 g of water at 20.1 °C in a calorimeter
Inessa [10]

Answer : The final temperature of the solution in the calorimeter is, 31.0^oC

Explanation :

First we have to calculate the heat produced.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = -44.5 kJ/mol

q = heat released = ?

m = mass of NaOH = 1.52 g

Molar mass of NaOH = 40 g/mol

\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{1.52g}{40g/mole}=0.038mole

Now put all the given values in the above formula, we get:

44.5kJ/mol=\frac{q}{0.038mol}

q=1.691kJ

Now we have to calculate the final temperature of solution in the calorimeter.

q=m\times c\times (T_2-T_1)

where,

q = heat produced = 1.691 kJ = 1691 J

m = mass of solution = 1.52 + 35.5 = 37.02 g

c = specific heat capacity of water = 4.18J/g^oC

T_1 = initial temperature = 20.1^oC

T_2 = final temperature = ?

Now put all the given values in the above formula, we get:

1691J=37.02g\times 4.18J/g^oC\times (T_2-20.1)

T_2=31.0^oC

Thus, the final temperature of the solution in the calorimeter is, 31.0^oC

4 0
3 years ago
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