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Len [333]
3 years ago
7

What would A be? HELP ASAP

Chemistry
1 answer:
Minchanka [31]3 years ago
6 0
Si has 4 available elections. Each Cl has 7.
7 x 4 = 28 + the 4 from your Si gives the total of 32 total electrons.
You might be interested in
What volume of water is needed for 0.196 mol of CdCl2 to prepare a 3.91 M solution? L
Brilliant_brown [7]

0.050 litres of the water will be required to make a 3.91 M solution with 0.196 moles in it.

Explanation:

Data given:

moles of CdCl_{2} = 0.196 Moles

Molarity of the solution = 3.91 M

Volume in litres =?

molarity is calculated by the formula:

molarity = \frac{number of moles}{volume in litres}

putting the values in the above formula and rearranging it for volume:

volume = \frac{number of moles}{molarity}

volume = \frac{0.196}{3.91}

volume = 0.050 litres

0.050 litres of the water will be required to make a 3.91 M solution with 0.196 moles in it.

Molarity is the number of moles present in a given volume of solution which is given in litres. It is the measurement of the concentration of particular solute in a solution.

4 0
3 years ago
The product of 173.06 times 0.21 should be reported as what using proper number of sig figs?
marissa [1.9K]

Answer:

36.3

Explanation:

The full answer would be 36.3426, but because of the 0.21, you round it down to 3 sig figs.

5 0
3 years ago
Write the empirical formula for at least four ionic compounds that could be formed from the following ions:
love history [14]

Answer:

FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}

Explanation:

Empirical formula of ionic compound formed by two ions A^{x+} and B^{y-} is A_{y}B_{x} (for x\neq y) of AB (for x = y)

The above empirical formula is in accordance with charge neutrality principle

Here each cation (Fe^{3+} and Fe^{2+}) can form two ionic compounds by combining with two given anions (SO_{4}^{2-} and CH_{3}CO^{2-}).

So the four ionic compounds are: FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}

4 0
4 years ago
the half life of the radioactive element strontium-90 is 29.1 years. If 16 grams of strontium-90 are initially present, how many
8_murik_8 [283]

Answer:

4 g after 58.2 years

0.0156 After 291 years

Explanation:

Given data:

Half-life of strontium-90 = 29.1 years

Initially present: 16g

mass present after 58.2 years =?

Mass present after 291 years =?

Solution:

Formula:

how much mass remains =1/ 2n (original mass) ……… (1)

Where “n” is the number of half lives

to find n

For 58.2 years

n = 58.2 years /29.1 years

n= 2

or  291 years

n = 291 years /29.1 years

n= 10

Put values in equation (1)

Mass after 58.2 years

mass remains =1/ 22 (16g)

mass remains =1/ 4 (16g)

 mass remains = 4g

Mass after 58.2 years

mass remains =1/ 210 (16g)

mass remains =1/ 1024 (16g)

mass remains = 0.0156g

8 0
3 years ago
Read 2 more answers
Does ccl4 has resonance structures
krek1111 [17]

Answer:

No, CCl₄ is 4 covalent C-Cl single bonds with a Tetrahedral geometry.

Explanation:l

For resonance structures to exist the molecule must have alternating single-double bonds. H₂C = CH - CH₃ <=> H₃C - CH = CH₂ resents a simple compound with a resonance structure system. This means that the π-bond electrons are distributed across all carbons in the molecular backbone. I would recommend internet searching for Danial Weeks 'Pushing Electrons' for a comprehensive review of molecular resonance structures. It is a brief, but easy to follow treatment of simple to complex structures containing resonance systems.

Hope this helps. Doc :-)

8 0
2 years ago
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