Charge on can A is positive.
Charge on can C is negative.
Punctuation and capitalization are very useful things to pay attention to and this question would be a lot easier to understand if you had actually used both capitalization and punctuation. If I'm understanding the question, you have 3 metal can that are insulated from the environment and initially touching each other in a straight line. Then a negatively charged balloon is brought near, but not touching one of the cans in that line of cans. While the balloon is near, the middle can is removed. Then you want to know the charge on the can that was nearest the balloon and the charge on the can that was furthermost from the balloon.
As the balloon is brought near to can a, the negative charge on the balloon repels some of the electrons from can a (like charges repel). Some of those electrons will flow to can b and in turn flow to can c. Basically you'll have a charge gradient that's most positive on that part of the can that's closest to the balloon, and most negative on the part of the cans that's furthest from the balloon. You then remove can B which causes cans A and C to be electrically isolated from each other and prevents the flow of elections to equalize the charges on cans A and C when the balloon is removed. So you're left with a deficiency of electrons on can A, so can A will have a positive overall charge, and an excess of electrons on can C, so can C will have a negative overall charge.
Answer:I think its the first one
Explanation:
Answer:
2800000J
Explanation:
Parameters given:
Mass = 920kg, weight = 920 * 9.8 = 9016N
Distance = 310m
Angle of inclination = 6.5°
Work done is given as :
W = F*d*cosA
Where A = angle of inclination
W = (9016 * 310 * cos6.5)
W = 2776993.59J
In 2 significant figures, W = 2800000J
Wavelength = (speed) / (frequency)
= (30 m/s) / (60/sec) =
= 0.5 meter .
Answer:
42.86m
Explanation:
The first thing we should keep in mind is that the watermelon moves with uniform acceleracion equal to gravity (9.81m / s ^ 2)
A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

where
Vf=29m/s= final speed
Vo= initial speed=0m/S
g=gravity=9.81m/s^2
Y= distance traveled(m)
solving

the distance traveled by watermelon is 42.86m