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Bas_tet [7]
1 year ago
4

A doubly ionized lithium atom is in the ground state. It absorbs energy and makes transition to the n = 5 excited state. The ion

returns to the ground state by emitting several photons. What is the wavelength of the highest energy photon?
Physics
1 answer:
Juli2301 [7.4K]1 year ago
7 0

The wavelength of highest photon energy is 0.544J.

  • Use the equation to calculate the electron's energy in the nth orbit.
  • Calculate the energies of the first and third Bohr orbits to determine the amount of energy needed to excite the electron.
  • The wavelength of a photon can be calculated using the photon energy formula.
  • Check how many different routes an excited electron can take to reach its ground state, the first Bohr orbit.
  • E=-\frac{13.6}{y^2}
  • E=-13.6/5²=0.544 J

To study about ground state -

<u>brainly.com/question/1314094</u>

#SPJ4

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three neutral metal cans mounted on isulating stands are touching a negatively charge ballon is brought near can a can b is then
Nimfa-mama [501]
Charge on can A is positive. 
Charge on can C is negative.  
Punctuation and capitalization are very useful things to pay attention to and this question would be a lot easier to understand if you had actually used both capitalization and punctuation. If I'm understanding the question, you have 3 metal can that are insulated from the environment and initially touching each other in a straight line. Then a negatively charged balloon is brought near, but not touching one of the cans in that line of cans. While the balloon is near, the middle can is removed. Then you want to know the charge on the can that was nearest the balloon and the charge on the can that was furthermost from the balloon. 
 As the balloon is brought near to can a, the negative charge on the balloon repels some of the electrons from can a (like charges repel). Some of those electrons will flow to can b and in turn flow to can c. Basically you'll have a charge gradient that's most positive on that part of the can that's closest to the balloon, and most negative on the part of the cans that's furthest from the balloon. You then remove can B which causes cans A and C to be electrically isolated from each other and prevents the flow of elections to equalize the charges on cans A and C when the balloon is removed. So you're left with a deficiency of electrons on can A, so can A will have a positive overall charge, and an excess of electrons on can C, so can C will have a negative overall charge.
7 0
3 years ago
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navik [9.2K]

Answer:I think its the first one

Explanation:

7 0
3 years ago
Read 2 more answers
What is the minimum work needed to push a 920-kg car 310 m up along a 6.5 ∘incline? Ignore friction.Express your answer using tw
AVprozaik [17]

Answer:

2800000J

Explanation:

Parameters given:

Mass = 920kg, weight = 920 * 9.8 = 9016N

Distance = 310m

Angle of inclination = 6.5°

Work done is given as :

W = F*d*cosA

Where A = angle of inclination

W = (9016 * 310 * cos6.5)

W = 2776993.59J

In 2 significant figures, W = 2800000J

7 0
3 years ago
La frecuencia de una onda es 60Hz y su velocidad, 30 m/s. Calcula su longitud de onda
Andreas93 [3]
           Wavelength = (speed) / (frequency)

                               =  (30 m/s) / (60/sec) =

                               =    0.5 meter .
3 0
4 years ago
A student wishes to record a 7.5-kilogram watermelon colliding with the ground. Calculate how far the watermelon must fall freel
algol [13]

Answer:

42.86m

Explanation:

The first thing we should keep in mind is that the watermelon moves with uniform acceleracion equal to gravity (9.81m / s ^ 2)

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

\frac {Vf^{2}-Vo^2}{2.g} =Y

where

Vf=29m/s= final speed

Vo= initial speed=0m/S

g=gravity=9.81m/s^2

Y= distance traveled(m)

solving

\frac {Vf^{2}-Vo^2}{2.g} =Y\\\frac {(29m/s)^{2}-(0m/s)^2}{2(9.8m/s^2)} =Y\\Y=42.86m\\

the distance traveled by watermelon is 42.86m

       

5 0
4 years ago
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