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lukranit [14]
1 year ago
9

Identify indicators of a chemical reaction. check all of the boxes that apply. a black powder is added to a clear liquid. fizzin

g and bubbling occur, and the test tube becomes hot to the touch. formation of a gas emission of light emission of heat
Chemistry
1 answer:
AnnyKZ [126]1 year ago
5 0

On top of a clear liquid, a black powder is put. The test tube starts to fizz and bubble, and it also gets hot to the touch. A gas is formed, and then there is a color change from the light and heat it emission.

Light may be absorbed and emitted by atoms and molecules, which allows us to determine the number of energy levels an electron has as well as the distance between those levels. The photon energies that correspond to various colors of light vary. In essence, a photon is a bundle of light. A photon of red light would have less energy than a photon of blue light, for instance. Red and blue have different wavelengths, and since red has a longer wavelength than blue, it has a lower energy. Only in shells, which surround nuclei, do electrons actually exist. Shells are matched to specific energy levels. The process of emission is the release of various colour photons by elements as their atoms decelerate to lower energies. When heated or stimulated, atoms release light.

Learn more about emission here:

brainly.com/question/517329

#SPJ4

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Copper (II) sulfate pentahydrate may be heated to drive off the water of hydration. If 5 g of water are produced, what was the o
____ [38]

Answer:

13.9g of CuSO4•5H2O

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CuSO4•5H2O → CuSO4 + 5H2O

Next, we shall determine the mass of CuSO4•5H2O heated and the mass of H2O produced from the balanced equation.

This is illustrated below

Molar mass of CuSO4• 5H2O = 63.5 + 32 + (16x4) + 5(2x1 + 16)

= 63.5 + 32 + 64 + 5(18) = 249.5g/mol

Mass of CuSO4•5H2O from the balanced equation = 1 x 249.5 = 249.5g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 5 x 18 = 90g

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Now, we can determine the mass of CuSO4•5H2O needed to produce 5g of H2O. This can be achieved as shown below:

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Therefore, Xg of CuSO4•5H2O will produce 5g of H2O i.e

Xg of CuSO4•5H2O = (249.5 x 5)/90

Xg of CuSO4•5H2O = 13.9g

Therefore, 13.9g of CuSO4•5H2O is needed to produce 5g of H2O.

6 0
3 years ago
During the reaction of 2,4-dinitrofluorobenzene with methoxide in methanol it was observed that it occurs at a significantly hig
Pachacha [2.7K]

Answer:

Explanation:

your not so smart

3 0
3 years ago
A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula?
Inessa [10]

A sample of a compound contains 60.0 g C and 5.05 g H.

divide by molar mass of C(12) and H(1) to get molar ratio

C: 60/12=5 and H: 5/1=5

so C:H=5:5=1:1

total molar mass=78

divide by 1C+1H to find the formula: 78/(12+1)=78/13=6

compound is C6H6


5 0
4 years ago
Read 2 more answers
A glucose solution that is prepared for a patient should have a concentration of 180 g/L. A nurse has 18 g of glucose. How many
Anuta_ua [19.1K]
You start by using proportions to find the number of liters of solution:

180 g of glucose / 1 liter of solution = 18 g of glucose / x liter of solution


=> x = 18 g of glucose * 1 liter of solution / 180 g of glucose = 0.1 liter of solution.


If you assume that the 18 grams of glucose does not apport volume to the solution but that the volume of the solution is the same volumen of water added (which is the best assumption you can do given that you do not know the how much the 18 g of glucose affect the volume of the solution) then you should add 0.1 liter of water.

Answer: 0.1 liter of water.

 
6 0
3 years ago
Read 2 more answers
What are the steps to finding an items density?
Assoli18 [71]
There are 5 steps:
1- measure the mass of the container
2- measure the volume of the liquid
3- measure the combined mass of the liquid and the container.
4-determine the mass of the liquid alone
5-divide the mass by the volume.
3 0
3 years ago
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