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lukranit [14]
1 year ago
9

Identify indicators of a chemical reaction. check all of the boxes that apply. a black powder is added to a clear liquid. fizzin

g and bubbling occur, and the test tube becomes hot to the touch. formation of a gas emission of light emission of heat
Chemistry
1 answer:
AnnyKZ [126]1 year ago
5 0

On top of a clear liquid, a black powder is put. The test tube starts to fizz and bubble, and it also gets hot to the touch. A gas is formed, and then there is a color change from the light and heat it emission.

Light may be absorbed and emitted by atoms and molecules, which allows us to determine the number of energy levels an electron has as well as the distance between those levels. The photon energies that correspond to various colors of light vary. In essence, a photon is a bundle of light. A photon of red light would have less energy than a photon of blue light, for instance. Red and blue have different wavelengths, and since red has a longer wavelength than blue, it has a lower energy. Only in shells, which surround nuclei, do electrons actually exist. Shells are matched to specific energy levels. The process of emission is the release of various colour photons by elements as their atoms decelerate to lower energies. When heated or stimulated, atoms release light.

Learn more about emission here:

brainly.com/question/517329

#SPJ4

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What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100g of the substance increases in te
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Explanation:

From the question given above, the following data were obtained:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature (ΔT). This can be obtained as follow:

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Change in temperature (ΔT) =?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 70 – 10

Change in temperature (ΔT) = 60 °C

Finally, we shall determine the specific heat capacity of the substance as follow:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) =?

Q = MCΔT

2500 = 100 × C × 60

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C = 2500 / 6000

C = 0.417 J/gºC

Therefore, the specific heat capacity of substance is 0.417 J/gºC

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