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Readme [11.4K]
4 years ago
15

A substance has a atomic number of 80.How many protons and electrons do atoms of the substance have ?what is the substance

Chemistry
2 answers:
otez555 [7]4 years ago
7 0

Answer:

Substance is Mercury (Hg)

             number of protons = 80

             number of electrons = 80

Anarel [89]4 years ago
4 0

Answer: Substance is Mercury (Hg)

              number of protons = 80

              number of electrons = 80

Explanation:

Atomic number which is symbolized by "Z" is the number of protons in nucleus of an atom.

Hence,

     number of protons = atomic number = 80

  • By knowing atomic number, we can find the element by using periodic table. Since the atomic number 80, the element is Mercury (Hg).

If the substance is in its neutral state, which means there is no charge on it, then the number of protons equals to the number of electrons of that element.

Hence,

   number of electrons = number of protons = 80


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Read 2 more answers
A sample of gas occupies a volume of 61.5 mL . As it expands, it does 130.1 J of work on its surroundings at a constant pressure
Lesechka [4]

Answer:

the final volume of the gas is V_2 = 1311.5 mL

Explanation:

Given that:

a sample gas has an initial volume of 61.5 mL

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The objective is to determine the final volume of the gas.

Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.

Converting the external pressure to atm ; we have

External Pressure P_{ext}:

P_{ext} = 783 \ torr \times \dfrac{1 \ atm}{760 \ torr}

P_{ext} = 1.03 \ atm

The workdone W = P_{ext}V

The change in volume ΔV= \dfrac{W}{P_{ext}}

ΔV = \dfrac{130.1 \ J  \times \dfrac{1 \ L  \ atm}{ 101.325 \ J}  }{1.03 \ atm }

ΔV = \dfrac{1.28398717 }{1.03  }

ΔV = 1.25 L

ΔV = 1250 mL

Recall that the initial  volume = 61.5 mL

The change in volume V is \Delta V = V_2 -V_1

-  V_2= -  \Delta V  -V_1

multiply through by (-), we have:

V_2=   \Delta V+V_1

V_2 =  1250 mL + 61.5 mL

V_2 = 1311.5 mL

∴ the final volume of the gas is V_2 = 1311.5 mL

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3 years ago
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