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OlgaM077 [116]
1 year ago
14

A missile is moving 1810 m/s ata 20.0° angle. It needs to hit atarget 19,500 m away in a 32.0°direction in 9.20 s. What is thema

gnitude of the accelerationthat the engine must produce?

Physics
1 answer:
garri49 [273]1 year ago
3 0

First let's calculate the vertical and horizontal components of the distance:

\begin{gathered} dh=19500\cdot\cos (32\degree) \\ dh=16536.94 \\  \\ dy=19500\cdot\sin (32\degree) \\ dy=10333.43 \end{gathered}

Then, since we have the time required, let's find the speed in each direction:

\begin{gathered} vh=\frac{dh}{t} \\ vh=\frac{16536.94}{9.2} \\ vh=1797.49 \\  \\ vy=\frac{dy}{t} \\ vy=\frac{10333.43}{9.2} \\ vy=1123.2 \end{gathered}

Now, let's decompose the given speed in its components:

\begin{gathered} Vh=1810\cdot\cos (20\degree) \\ Vh=1700.84 \\  \\ Vy=1810\cdot\sin (20\degree) \\ Vy=619.06 \end{gathered}

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A tire sits atop a ramp. When the tire is released, it rolls down the ramp. At the ramp's bottom, the speeding tire knocks down
k0ka [10]

Answer:

mechanical energy

Explanation:

Mechanical energy is the combination of both potential energy and kinetic

Mechanical energy can be divided as

1)kinetic energy, this energy vis regarded as the energy of motion

2) potential energy which is the stored energy of position.

Mechanical energy reffered to as

motion energy this energy is responsible for the movement of an object based on its position as well as motion.

Mechanical energy= U + K

Where U= potential energy

K= Kinectic energy

As the tire is sitting on top of a ramp, it posses "potential energy" as it is released and rolls down the ramp the potential is converted to Kinectic energy

4 0
2 years ago
A bug is sitting on the edge of a rotating disk. At what angular velocity will the bug slide off the disk if its radius is 0.241
Ivahew [28]

Answer:

ω = 3.61 rad/sec

Explanation:

Firstly, we should know that the bug will not slip if friction can provide sufficient opposing force.

μmg = mv^2/r = mω^2r

Thus;

μg = ω^2r

ω^2 = μg/r

ω = √(μg/r)

ω = √(0.321 * 9.8)/0.241

ω = √(13.05)

= 3.61 rad/sec

3 0
3 years ago
A person on a daily diet of 2,500 calories should get no_more than <br> calories from fat each day.
ivann1987 [24]

Answer:

35%

Explanation:

3 0
3 years ago
Read 2 more answers
how much gravitational potential energy do you give a 70 kg person when you lift him up 3 m in the air?
SCORPION-xisa [38]

Given gravitational potential energy when he's lifted is 2058 J.

Kinetic energy is transferred to the person.

Amount of kinetic energy the person has is -2058 J

velocity of person = 7.67 m/s².

<h3>Explanation:</h3>

Given:

Weight of person = 70 kg

Lifted height = 3 m

1. Gravitational potential energy of a lifted person is equal to the work done.

PE_g=W=m\times g\times h\\Acceleration due to gravity = g = 9.8 \ m/s^2 \\PE_g= m = m\times g\times h= 70\times 9.8 \times 3 = 2058\ kg.m/s^2 = 2058\ J

Gravitational potential energy is equal to 2058 Joules.

2. The Gravitational potential energy is converted into kinetic energy. Kinetic energy is being transferred to the person.

3. Kinetic energy gained = Potential energy lost = -PE_g = -2058\ kg.m/s^2

Kinetic energy gained by the person = (-2058 kg.m/s²)

4. Velocity = ?

Kinetic energy magnitude= \frac{1}{2} m\times v^2 = m\times g \times h

Solving for v, we get

v=\sqrt{2gh} =\sqrt{2\times 9.8 \times 3} = \sqrt{58.8} = 7.67 m/s^2

The person will be going at a speed of 7.67 m/s².

4 0
3 years ago
You are riding in a vehicle with a coffee cup on the dashboard while traveling 30 km/h. The vehicle makes a sudden stop to avoid
wariber [46]

Answer:

It would move forward.

Explanation:

3 0
3 years ago
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