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2 years ago

How much force is on a cart when the acceleration of the cart is 2.6 m/s2

Physics

1 answer:

alexdok [17]2 years ago

8 0

Answer:

F = 13N

Explanation:

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A campground official wants to measure the distance across an irregularly-shaped lake, but can't do so directly. He picks a poin

sleet_krkn [62]

Answer:

149 m

Explanation:

The distances across the lake is forming a triangle.

let the distance between the point and the left side be 'x'

and the distance between the point and the right be 'y'

and the distance across the lake be 'z' and the angle opposite to 'z' be 'Z' given:

∠Z = 83°

x = 105 m

y = 119 m

Now, applying the Law of Cosines, we get

z² = x² + y² - 2xycos(Z)

Substituting the values in the above equation, we get

z² = 105² + 119² - 2×105×119×cos(83°)

z = √22140.48

z = 148.796 m ≈ 149 m

The point is 149 m across the lake

8 0

3 years ago

At which of the following air temperatures will the

monitta

Answer:

The answer is: B. -487 ..............

3 0

3 years ago

Why is argon gas used instead of air in light bulbs that contain a filament that is heated to glowing?

tamaranim1 [39]

<span>the heated filament will react with the oxygen in the air but now with the argon, which is a noble gas and hardly ever reacts.</span>

3 0

3 years ago

A balloon having an initial temperature of 17.8Â°C is heated so that the volume doubles while the pressure is kept fixed. What i

Rama09 [41]

Answer:

$T = 308.6 ^0 C$

Explanation:

Here by ideal gas equation we can say

$PV = nRT$

now we know that pressure is kept constant here

so we will have

$V = \frac{nR}{P} T$

since we know that number of moles and pressure is constant here

so we have

$\frac{V_2}{V_1} = \frac{T_2}{T_1}$

now we know that initial temperature is 17.8 degree C

and finally volume is doubled

So we have

$\frac{2V}{V} = \frac{T_2}{(273 + 17.8)}$

so final temperature will be

$T_2 = 581.6 k$

$T_2 = 308.6 ^o C$

5 0

3 years ago

At a dock, a crane lifts a 2009 kg container 20 m, swings it out over the deck of a freighter, and lowers the container into the

deff fn [24]

Answer:

W = 157.5kJ

Explanation:

Assuming it moves the container at constant speed, the work done by the crane will be equal to the variation of the potential gratitational energy on the container:

$Wc = \Delta E = m*g*(h2 - h1)$ where h2= -8m and h1=0m

Wc = 157.5kJ

6 0

3 years ago