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3 years ago

A car is traveling at 100 km/h. How many minutes will it take to cover a distance of 750 km?

Physics

1 answer:

Ahat [919]3 years ago

8 0

Answer:

7.5 minutes (you mean hours)

t = 7.5 min (if it was actually not hours than put minutes just letting u know.)

Explanation:

The first thing you have to do is know the equation; it is t = d/s, which is time = distance divided by speed. Know fill in the equation, now it will be t = 750 km/100 km/ hr ( in this min). If you divide it, then the answer will be t = 7.5 min (which it has to be hours instead of min because hours makes more sense than minutes.)

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3 years ago

Romeo traveled by a 900 kg horse from Manitua to Verona accelerating at the rate of 20 km/hr. With what force is Romeo moving at

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Answer:

Force(Romeo moving) = 5,000 N

Explanation:

Given:

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3 years ago

Radiant heat makes it impossible to stand close to a hot lava flow. Calculate the rate of heat loss by radiation from 1.00 m^2 o

VARVARA [1.3K]

The rate of heat loss by radiation is equal to <u>-207.5kW</u>

Why?

To calculate the heat loss rate (or heat transfer rate) by radiation, from the given situation, we can use the following formula:

$HeatLossRate=E*S*A*((T_{cold})^{4} -(T_{hot})^{4} )$

Where,

E, is the emissivity of the body.

A, is the area of the body.

T, are the temperatures.

S, is the Stefan-Boltzmann constant, which is equal to:

$5.67x10^{-8}\frac{W}{m^{2}*K^{-4} }$

Now, before substitute the given information, we must remember that the given formula works with absolute temperatures (Kelvin), so, we need to convert the given values of temperature from Celsius degrees to Kelvin.

We know that:

$K=Celsius+273.15$

So, converting we have:

$T_{1}=1110\°C+273.15=1383.15K\\\\T_{2}=36.2\°C+273.15=309.35K$

Therefore, substituting the given information and calculating, we have:

$HeatLossRate=E*S*A*((T_{cold})^{4} -(T_{hot})^{4} )$

$HeatLossRate=1*5.67x10^{-8}\frac{W}{m^{2}*K^{-4} }*1m^{2} *((309.35K)^{4} -(1383.15})^{4} )\\\\HeatLossRate=5.67x10^{-8}\frac{W}{K^{-4} }*(95697.42K^{4} -3.66x10^{12}K^{4})\\ \\HeatLossRate=5.67x10^{-8}\frac{W}{K^{-4} }*(-3.66x10^{12} K^{4})=-207522W=-207.5kW$

Hence, we have that the rate of heat loss is equal to -207.5kW.

8 0

3 years ago

Suppose a spring has a relaxed length of 28.3 cm. The simulation refers to this as the natural length. This is the length of the

den301095 [7]

Answer:

Explanation:

Normal length of spring = 28.3 cm

stretched length of spring = 38.2 cm

length of extension = 38.2 - 28.3 = 9.9 cm

= 9.9 x 10⁻² m

force applied to stretch = .55 x 9.8 ( mg )

= 5.39 N

Force constant = force applied / extension

= 5.39 / 9.9 x 10⁻²

= .5444 x 10² N /m

= 54.44 N/m

4 0

3 years ago

A car is traveling at 100 km/h. How many minutes will it take to cover a distance of 750 km￼￼?

A car is traveling at 100 km/h. How many minutes will it take to cover a distance of 750 km?