Answer:
59.76 grams of Li₂O
Explanation:
To solve this problem we will first calculate the moles of Li₂O. One mole of given substance always contains 6.022 × 10²³ particles which can be atoms, ions, molecules or formula units. This number is also called as Avogadro's Number.
The relation between Moles, Number of Particles and Avogadro's Number is given as,
Number of Moles = Number of Particles ÷ 6.022 × 10²³
Putting values,
Number of Moles = 1.204 × 10²⁴ Particles ÷ 6.022 × 10²³
Number of Moles = 2.0 Moles
Secondly, we will convert calculated moles to mass using following relationship.
Moles = Mass / M.Mass
Or,
Mass = Moles × M.Mass
Putting values,
Mass = 2.0 mol × 29.88 g/mol
Mass = 59.76 grams of Li₂O
sodium element is likely to have the highest thermal conductivity
Answer:
Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution
Explanation:
As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.
When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.
This gas turn red litmus paper blue.
This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).
If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.
