Answer:
d) 0.1202 M
Explanation:
Let's consider the neutralization reaction between NaOH and a generic monoprotic acid.
NaOH + HA → NaA + H₂O
The used volume of NaOH is 41.63 mL - 19.63 mL = 22.00 mL. The moles of NaOH are:
22.00 × 10⁻³ L × 0.1093 mol/L = 2.405 × 10⁻³ mol
The molar ratio of NaOH to HA is 1:1. The moles of HA that reacted are 2.405 × 10⁻³ moles.
The molar concentration of HA is:
2.405 × 10⁻³ mol / 20.00 × 10⁻³ L = 0.1202 M
It would be (1) magnesium.
hope this helps :D
Answer:
you need to use the of the five to the report to the report that there are two different and the other two are the same limited as the or the two of the 8
Explanation:
get
Explanation:
we know that 0.250 L = 0.250 dm3
molarity = concentration in dm3/ volume
molarity = 0.175/0.250 = 0.7 mol/dm3
