Which of the followings are not the receptor

How many grams are in 0.220 mol of Ne?

yawa3891 [41]

Answer:

Mass = 4.44 g

Explanation:

Given data:

Number of moles of Ne = 0.220 mol

Mass in gram = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of Ne = 20.2 g/mol

by putting values,

0.220 mol = mass/ 20.2 g/mol

Mass = 0.220 mol × 20.2 g/mol

Mass = 4.44 g

5 0

3 years ago

A compound of formula XCl3 reacts with aqueous AgNO3 to yield solid AgCl according to the following equation: XCl3(aq)+3AgNO3(aq

Levart [38]

Answer:

Aluminum

Explanation:

$Moles =\frac {Given\ mass}{Molar\ mass}$

Mass of $AgCl$ = 1.68 g

Molar mass of $AgCl$ = 143.32 g/mol

Thus,

$Moles\ of\ AgCl=\frac {1.68}{169.87}=0.01172$

From the reaction below:

$XCl_3_{(aq)}+3AgNO_3_{(aq)}\rightarrow X(NO_3)_3_{(aq)}+3AgCl_{(s)}$

3 moles of $AgCl$ are produced when 1 mole of $XCl_3$ undergoes reaction.

So,

1 mole of $AgCl$ are produced when $\frac {1}{3}$ mole of $XCl_3$ undergoes reaction.

0.01172 mole of $AgCl$ are produced when $\frac {1}{3}\times 0.01172$ mole of $XCl_3$ undergoes reaction.

Thus, moles of $XCl_3$ = 0.0039 moles

Let the atomic mass of X = x g/mol

atomic mass of chlorine = 35.5 g/mol

Thus, Molar mass of $XCl_3$ = x + 3(35.5) g/mol = x + 106.5 g/mol

Moles = 0.0039 moles

Mass = 0.521 g

Thus, molar mass = Given mass/ Moles = 0.521 / 0.0039 = 133.5897 g/mol

So,

x + 106.5 = 133.5897

x = 27.0897 g/mol

This Atomic weight corresponds to Aluminum. Hence, X is aluminum.

8 0

4 years ago

calculate atomic weight of silver which has two isotopes with the following properties : silver-107 (106.91 amu, 51.84% natural

Julli [10]

Answer: The atomic weight of silver is 107.87 amu

Explanation:

Mass of isotope silver-107 = 106.91 amu

% abundance of isotope silver -107 = 51.84% = $\frac{51.84}{100}=0.5184$

Mass of isotope silver-109 = 108.90 amu

% abundance of isotope silver-109 = 48.16% = $\frac{48.16}{100}=0.4816$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=\sum[(106.91\times 0.5184)+(108.90\times 0.4816)]$

$A=107.87amu$

Thus atomic weight of silver is 107.87 amu

8 0

4 years ago

A biochemist conducted an experiment to follow the movement of glucose molecules in animal cells. Glucose with radioactively lab

Airida [17]

Answer:

Here is a link I made for you

http://chs.helenaschools.org/wp-content/uploads/sites/32/2018/05/2016-2017-AP-Biology-Exam-Review.docx

Explanation:

This explanes all of what you need along with helpful videos an other things I found intersting for you HOPE IT HELPS YOU YOUR WELCOME.

6 0

3 years ago

Pyridine is a weak base that is used in the manufacture of pesticides and plastic resins. It is also a component of cigarette sm

Luda [366]

Answer:

pH of the solution = 9.45

Explanation:

pKb = 8.57

pKb = -logKb

Kb = antilog pkb

$K_b = 1.78 \times 10^{-9}$

ICE table for the ionization of pyrodine is:

$C_5H_5N+H_2O \leftrightharpoons C_5H_5NH^+ + OH^-$

initial 0.435 0 0

equi. 0.435 - x x x

so,

$k_b =\frac{ [C_5H_5NH^+][OH^-]}{[C_5H_5N]}\\1.78\times 10^{-9}=\frac{x^2}{0.453 - x}$

As kb is very less that means there is very less ionization, hence x can be ignored as compared to 0.435

$x^2 = 1.78\times 10{-9} \times 0.435\\x= 2.78\times 10^{-5}$

pOH = -log[OH-]

$pOH = -log[2.78\times 10^{-5}]\\=4.55$

pH = 14 - pOH

= 14 - 4.55

= 9.45

5 0

4 years ago