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Cerrena [4.2K]
1 year ago
11

In the gravimetric method, is it important that you dissolve your sample in exactly 10 ml of water? why or why not?.

Chemistry
1 answer:
alekssr [168]1 year ago
8 0

When utilizing the gravimetric method, it is crucial to completely dissolve your sample in 10 mL of water. A quantitative technique called gravimetric analysis employs the selective precipitation of the component under study from an aqueous solution.

A group of techniques known as gravimetric analysis are employed in analytical chemistry to quantify an analyte based on its mass. Gravimetric analysis is a quantitative chemical analysis technique that transforms the desired ingredient into a substance (of known composition) that can be extracted from the sample and weighed. This is a crucial point to remember.

Gravimetric water content (g) is therefore defined as the mass of water per mass of dry soil. To calculate it, weigh a sample of wet soil, dry it to remove the water, and then weigh the dried soil (mdry). Dimensions of the sample Water is commonly forgotten despite having a density close to one.

To know more about gravimetry, please refer:

brainly.com/question/18992495

#SPJ4

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A certain orbital of the hydrogen atom has n = 4 and l = 2 what are the possible values of ml for this orbital?
Nadya [2.5K]

The ml is also called as the magnetic quantum number. The value of ml can range from –l to +l including zero. Hence all of the possible values for ml given that l = 2 are:

<span>-2, -1, 0, + 1, + 2</span>

3 0
3 years ago
If a snail crawls at 0.013 m/s north, how far will it travel in 60 seconds? Find time.
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8 0
3 years ago
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**<br> H₂ + O2-&gt;<br> Balancing equations from a reaction
goblinko [34]

Answer:

2H2+O2->2H2O

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3 years ago
What is the independent variable?
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6 0
3 years ago
A pool is 59.8 m long and 26.6 m wide. If the average depth of water is 3.70 ft, what is the mass (in kg) of water in the pool?
klio [65]

Given :

Length , l = 59.8 m.

Breadth , b  = 26.6 m.

Depth , d = 3.7 ft .

Density of water , \rho=1\ g/ml=1000\ kg/m^3 .

To Find :

Mass of water in pool .

Solution :

First we will covert depth into m from ft .

1\ ft =0.3\ m

For ,

3.7\ ft=0.3\times 3.7\ m\\3.7\ ft=1.11\ m

So , volume of pool is :

V=59.8\times 26.6\times 1.11\ m^3\\\\V=1765.65\ m^3

We know , density is given by :

\rho=\dfrac{m}{V}

So , m=\rho V

Putting given values in above equation :

m=1000\times 1765.65\ kg\\\\m=1.77\times 10^6\ kg

Hence , this is the required solution.

7 0
3 years ago
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