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Cerrena [4.2K]
2 years ago
11

In the gravimetric method, is it important that you dissolve your sample in exactly 10 ml of water? why or why not?.

Chemistry
1 answer:
alekssr [168]2 years ago
8 0

When utilizing the gravimetric method, it is crucial to completely dissolve your sample in 10 mL of water. A quantitative technique called gravimetric analysis employs the selective precipitation of the component under study from an aqueous solution.

A group of techniques known as gravimetric analysis are employed in analytical chemistry to quantify an analyte based on its mass. Gravimetric analysis is a quantitative chemical analysis technique that transforms the desired ingredient into a substance (of known composition) that can be extracted from the sample and weighed. This is a crucial point to remember.

Gravimetric water content (g) is therefore defined as the mass of water per mass of dry soil. To calculate it, weigh a sample of wet soil, dry it to remove the water, and then weigh the dried soil (mdry). Dimensions of the sample Water is commonly forgotten despite having a density close to one.

To know more about gravimetry, please refer:

brainly.com/question/18992495

#SPJ4

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How many moles are there in each of 280g of silion​
nasty-shy [4]

Answer:

10 moles

Explanation:

of moles = given mass /atomic mass = 280 g /28 g = 10 moles of Si atoms in 280g sample.

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At 1115 degrees Celcius, where iron is still a solid (melting point 1538 degrees Celcius), the unit cell for the most stable cry
svp [43]

<u>Answer:</u> The atomic radius of iron is 128 pm.

<u>Explanation:</u>

To calculate the radius of the metal having FCC crystal lattice, the relationship between edge length and radius follows:

4r=\sqrt{2}a

Where,

a = edge length = 362 pm

r = atomic radius of iron = ?

Plugging values in above equation, we get:

r=\frac{\sqrt{2}\times 362}{4}\\\\a=128pm

Hence, the atomic radius of iron is 128 pm.

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Alborosie

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Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.
Maksim231197 [3]

The theoretical yield of SnS_2 will be 4.20 grams while the percent yield will be 7.93%

<h3>How is yield calculated?</h3>

From the equation of the reaction, the mole ratio of SnBr_4 to Na_2S is 1:2.

Mole of 48.1 mL, 0.478 M  SnBr_4 = 0.478 x 48.1/100 = 0.023 mols

Mole of 48.8 mL, 0.160 M   Na_2S = 0.160 x 48.8/1000 = 0.0078 moles

SnBr_4Na_2S is the limiting reactant.

Mole ratio of  SnBr_4  and SnS_2 = 1:1

Equivalent mole of  SnS_2 = 0.023 moles

Mass of 0.023 noles SnS_2= 0.023 x 182.81 = 4.20 grams

With 0.0333 g of SnS_2 recovered, percent yield = 0.333/4.2 x 100 = 7.93%

More on yields of reactions can be found here: brainly.com/question/17042787

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Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.

SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)

Suppose a student adds 48.1 mL of a 0.478 M solution of SnBr4 to 48.8 mL of a 0.160 M solution of Na2S.

1) Calculate the theoretical yield of SnS2. ;

2) The student recovers 0.333 g of SnS2. Calculate the percent yield of SnS2 that the student obtained.

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2 years ago
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