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NNADVOKAT [17]
1 year ago
13

a car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 24 ft/s2. what is the dist

ance (in ft) traveled before the car comes to a stop? (round your answer to one decimal place.) 52.1 incorrect: your answer is incorrect. ft
Physics
1 answer:
Maslowich1 year ago
4 0

One of the key areas of science is the study of acceleration and deceleration. Any object's rate of changing velocity is referred to as its acceleration, and a negative acceleration value is referred to as deceleration.

Using beginning velocity of 50 miles per hour,

It's going to

Final speed: 73.33 ft/s, v = 0, and a2: -22 ft/s2.

Utilize the formula: v2 = v0 + 2as

n 0 = 5377.29 + (-44) s

s =5377.29/44 = 122.21 ft

v2 = u2 + 2as is the third equation of motion. We are already aware that distance is equal to average velocity times time. Either v2 = u2 + 2as or 2as = v2 - u2. The third equation of motion connects the particle's final velocity (v), initial velocity (u), constant speed (a), and displacement (S).

Speed is defined as the ratio of distance travelled to the amount of time required to cover that distance.

To know more about motion, click on the link below:

brainly.com/question/14812762

#SPJ4

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