Arsenic in period 4 group 5.
Answer:
(a) Jx = -1.14Ns, Jy = 110×3×10-³ = 0.330Ns (b) V = (0m/s)ı^−(1.79m/s)ȷ^
Explanation:
Given
W = 0.56N = mg
m = 0.56/g = 0.56/9.8 = 0.057kg
t = 3.00ms = 3.00×10-³s
Impulse is a vector quantity so we would treat it as such
We have been given the force and velocity in their component forms so to get the impulse from these quantities, we pick the respective component for the quantity we want to calculate and do the necessary calculation. The masses are scalar quantities and so do not affect the signs used in the calculations whether positive or negative. So we have that
u = (20.0m/s)ı^−(4.0m/s)ȷ^
ux = 20m/s
uy = – 4.0m/s
F = – (380N)ı^+(110N)ȷ^
Fx = –380N
Fy = 110N
J = impulse = force × time = F×t
So Jx = Fx ×t
Jy = Fy×t
Jx = –380×3×10-³ = -1.14Ns
Jy = 110×3×10-³ = 0.330Ns
Impulse also equals the change in momentum of the body. So
J = m(v–u)
J/m = v – u
V= J/m + u
Vx = Jx/m + ux
Vx = –1.14/0.057 + 20
Vx = -20 + 20 = 0m/s
Vx = 0m/s
Vy= Jy/m + uy
Vy= 0.33/0.057 + (-4.0)
Vy= 5.79 + (-4.0) = 1.79m/s
V = (0m/s)ı^−(1.79m/s)ȷ^
<span> For this case we have the following number:
1,000,000
We note that the number has 7 significant figures.
To write it in scientific notation we must write the number as follows:
</span>
<span> Where,
a: first significant figure
b: Exponent that represents the rest of significant figures.
Rewriting the number we have:
</span>
<span>
Answer: 1,000,000 to scientific notation is:</span>
<span>
</span>
Answer:
14.17H
Explanation:
Energy stored in an inductor is expressed as;
E = 1/2LI²
L is the inductance of the inductor
I is the current flowing through the inductor
Given
E = 10.2J
I = 1.20
Required
Inductance L
Substitute the given parameters into the formula;
10.2 = 1/2L(1.2)²
10.2 = 1/2*1.44L
10.2 = 0.72L
L = 10.2/0.72
L = 14.17H
Hence the self inductance of the solenoid is 14.17H
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