All categories

3 years ago

What type of modulation is typically used by broadcasting stations to transmit pictures on television screens?

Physics

2 answers:

katovenus [111]3 years ago

8 0

Answer:

A. Amplitude

Explanation:

i think based on quizlets

erik [133]3 years ago

4 0

Answer:

The correct option is;

Amplitude

Explanation:

When transmitting picture signals over the air by broadcasting stations, the signals are shifted into high frequency channels of Very High Frequency (VHF) or Ultra High Frequency (UHF) carrier currents and imposing the the television signal by changing the amplitude of the high frequency carrier current to match the transmitted television signal waveform shape

You might be interested in

Children are ready for more complex storybooks:

FromTheMoon [43]

Answer:

Explanation:

Because that is when they're mind learns how to read

5 0

3 years ago

A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 65 m/s in 5 seconds. Wha

vekshin1

Acceleration = (change in speed) / (time for the change)

Change in speed = (speed after the change) - (speed before the change)

Change in speed = (65 m/s) - (35 m/s) = 30 m/s

Acceleration = (30 m/s) / (5 s)

Acceleration = 6 m/s²

7 0

4 years ago

18°C = _____ A -255 K B- 0 K C- 18 K D- 291 K

mariarad [96]

Answer:

291 K is the answer

Explanation:

to get Kelvin from Celsius use the following

Kelvin = Celsius +273

= 18 +273

= 291

7 0

3 years ago

When did the object have the highest average

miv72 [106K]

Answer:

Between 120 and 180 seconds

7 0

3 years ago

A surface receiving sound is moved from its original position to a position three times farther away from the source of the soun

vazorg [7]

Answer:

c. nine times as low.

Explanation:

Sound intensity is defined as the acoustic power transferred by a sound wave per unit of normal area to the direction of propagation:

$I\propto \frac{1}{A}$

Since the sound wave has a spherical wavefront of radius r, then the area is given by:

$A=4\pi r^2$

Here r is the distance from the source of the sound. Thus sound intensity decreases as:

$I\propto \frac{1}{4\pi r^2}\\\\I'\propto \frac{1}{4\pi r'^2}\\\\I'\propto \frac{1}{4\pi (3r)^2}\\\\I'\propto \frac{1}{9} \frac{1}{4\pi r^2}\\\\I'\propto \frac{1}{9} I$

6 0

4 years ago