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8 months ago

Which color in the rainbow has the longest wavelength? 1. orange 2. blue3. yellow4.green 5. red

Chemistry

1 answer:

rodikova [14]8 months ago

6 0

In rainbow, the color that has the longest wavelength is red which means option 5 is the correct choice.

Dispersion is described to be the spreading of white mild into its complete spectrum of colors, in truth we also can say a complete spectrum of wavelengths. The white mild turns into from solar and includes seven colors. On one end of the spectrum is red with the longest wavelength. Blue or violet mild has the shortest wavelength. White mild is a aggregate of all hues withinside the color spectrum. The colors of the rainbow are: Red, orange, yellow, green, blue, indigo, violet.

Therefore, option 5 is the correct choice.

To learn more about rainbow check the link below:

brainly.com/question/12008276

#SPJ4

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Determine the method to separate a mixture of ground glass and salt in order to have a pile of ground glass and another pile of

Serga [27]

1 Water is added to the mixture of ground glass and salt to dissolve the salt content

2 The mixture is then filtered leaving the grounded glass particles in the sieve

3 The salt is then evaporated leaving the salt crystals

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2 years ago

A sample of neon occupies a volume of 752 ml at 25 0

lyudmila [28]

$V_{initial} = 752\:mL$
$T_{initial} = 25.0^0C$
converting to Kelvin
TK = TC + 273
TK = 25.0 + 273 → TK = 298.0 → $T_{initial} = 298.0\:K$
$V_{final} = ? (in\:milliliters)$
$T_{final} = 50.0^0C$
TK = TC + 273
TK = 50.0 + 273 → TK = 323.0 → $T_{final} = 323.0\:K$

By the first Law of Charles and Gay-Lussac, we have:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$

Solving:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$
$\frac{ 752 }{ 298.0 } = \frac{ V_{f} }{ 323.0 }$
Product of extremes equals product of means:
$298.0* V_{f} = 752*323.0$
$298.0 V_{f} = 242896$
$V_{f} = \frac{242896}{298.0}$
$\boxed{\boxed{V_{f} \approx 815.08\:mL}}\end{array}}\qquad\quad\checkmark$

5 0

3 years ago

jake pushes a heavy box across a carpeted floor.Name three forces that act on the box, and explain how you know these are unbale

Fantom [35]

I actually learned about this stuff about 3 years ago and this is what I can tell you what I remember and hopefully it helps in a way...
[Newton’s law of motion]
There’s unbalanced forces, friction, and balanced forces.
Unbalanced forces is where the object (in this case the box) is moving in one direction because one of the forces is applying more pressure than the other
Friction is where the box would be harder to push but if it’s still an unbalanced force, it will still move in one direction. The surfaces of the ground and or object isn’t smooth. Therefore creating difficulty when moving it.
A Balanced force will not move the object in any direction. This is because there is an equal amount of force being applied to all opposing sides. The net force will always equal 0 when there’s a balanced force!

-HOPE THAT HELPED IN A WAY! <3

6 0

3 years ago

Which statement explains how the charges on objects determine the electric force between them?(1 point)

lubasha [3.4K]

Answer:

Objects with the same charge repel each other, and objects with opposite charges attract each other.

Explanation:

The Coulomb law states that opposite charges attract each other and like charges repel each other. That means two positive charges repel each other but a positive and a negative charge attract.

8 0

1 year ago

Read 2 more answers

Butane (C4 H10(g), Hf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , Hf = –393.5 kJ/mol ) and water (H2 O,

WITCHER [35]

Answer: Enthalpy of combustion (per mole) of $C_4H_{10} (g)$ is -2657.5 kJ

Explanation:

The chemical equation for the combustion of butane follows:

$2C_4H_{10}(g)+4O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(8\times \Delta H^o_f_{CO_2(g)})+(10\times \Delta H^o_f_{H_2O(g)})]-[(1\times \Delta H^o_f_{C_4H_{10}(g)})+(4\times \Delta H^o_f_{O_2(g)})]$

We are given:

$\Delta H^o_f_{(C_4H_{10}(g))}=-125.6kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-241.82kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_{rxn}=?$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.6)+(4\times 0)]\\\\\Delta H^o_{rxn}=-5315kJ$

Enthalpy of combustion (per mole) of $C_4H_{10} (g)$ is -2657.5 kJ

6 0

2 years ago