Answer:
511.1 J
Explanation:
We are given that 
Mass of wood block=m=3 kg
Vertical distance,h=23 m
Horizontal distance =x=30 m
Distance traveled in downward direction y=40 m
Initial velocity,u=0

Where 






By work energy theorem 
Change in kinetic energy=Work done= mgh-W



Hence, the work done due to friction on the block as it slides down the ramp=511.1 J
 
        
             
        
        
        
B they help visualize things that are very complex, very large, or very small.
        
                    
             
        
        
        
I'm pretty sure it's the<span> impact of the air molecules on the outside of the stopper. They exert a net inward force, which is not resisted by anything on the other side.</span>
        
                    
             
        
        
        
Answer:
The Hydrostatic force is   
The location of pressure center is   
  
Explanation:
From the question we are told that 
    The height of the gate is  
      The weight of the gate is  
       The height of the water is  
        The density of water is 
 
Note used  for height of water and height of gate immersed by water since both have the same value
 for height of water and height of gate immersed by water since both have the same value 
The area of the gate immersed in water  is mathematically represented as 
          
substituting values 
          
          
 The hydrostatic force is mathematically represented as
           
Where 
             
            
             
  
So  
               
             
The center of pressure is mathematically represented as 
         
Where  is the moment of inertia of the gate which mathematically represented as
 is the moment of inertia of the gate which mathematically represented as 
             
The  is the height of gate immersed in water
 is the height of gate immersed in water 
              
 
               
 
Thus  
         
         
 
        
             
        
        
        
When the body is at rest, its speed is zero, and the graph lies on the x-axis.
When the body is in uniform motion, the speed is constant, and the graph is a horizontal line, parallel to the x-axis and some distance above it.
It's impossible to tell, based on the given information, how these two parts of the 
graph are connected.  There must be some sloping (accelerated) portion of the graph
that joins the two sections, but it cannot be accounted for in either the statement 
that the body is at rest or that it is in uniform motion, since acceleration ... that is, 
any change of speed or direction ... is not 'uniform' motion'.