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marissa [1.9K]
3 years ago
15

A teacher tells her​ students, "When you do your math homework​ assignments, you must use white lined paper.​ Please, no​ tear-o

uts from spiral notebookslong dashI ​won't accept them under any​ circumstances! Divide each page with a vertical​ line, always putting the problem on the left side and your solution on the right side. Use a number two pencillong dashnothing ​lighter, and definitely no​ ink! I expect all erasures to be thorough and​ clean." Which one of the following basic needs is the teacher most likely to be putting in jeopardy​ here?
Engineering
1 answer:
Sindrei [870]3 years ago
8 0

Answer:

The white lined paper

Explanation:

The teacher is most likely putting the while line paper in jeopardy because of the detail process involved in taking care of the paper prior to the submission of the home work.

The fact that a mistake must not be visible due to the instruction of every erasures being thorough and clean.  this can cause jeopardy to the paper.

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State two main consumers of electricity transmitted at low frequency Calculate the primary voltage of a transformer if the prima
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Answer:

1) a. Customers requiring AC electric power transmission for powering remote devices which may include a subsea transmission system where power is distributed to subsea devices

b. Customers that utilize commutator-type motors

2) The primary voltage is 150 volts

Explanation:

The parameters given are;

Number of primary winding, N_p = 50 turns

Number of secondary winding, N_s = 150 turns

Voltage in secondary winding, V_s = 450 volts

Voltage in primary winding = V_p

The relation between N_p, N_s, V_s and V_p is as follows;

\dfrac{V_p}{V_s}  = \dfrac{N_p}{N_s}

Which gives;

V_p  = \dfrac{N_p \times V_s}{N_s}

From which we have;

V_p  = \dfrac{50\times 450}{150} = 150 \ volts

The primary voltage = 150 volts.

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Answer:

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An Ideal gas is being heated in a circular duct as while flowing over an electric heater of 130 kW. The diameter of duct is 500
aleksandrvk [35]

Answer:

Exit temperature = 32°C

Explanation:

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Initial Pressure;P1 = 100 KPa

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Initial temperature;T1 = 27°C = 273 + 27K = 300 K

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W = 130 Kw

Q = 80 Kw

Using ideal gas equation,

PV' = m'RT

Where m' is mass flow rate.

Thus;making m' the subject, we have;

m' = PV'/RT

So at inlet,

m' = P1•V1'/(R•T1)

m' = (100 × 15)/(0.5 × 300)

m' = 10 kg/s

From steady flow energy equation, we know that;

m'•h1 + Q = m'h2 + W

Dividing through by m', we have;

h1 + Q/m' = h2 + W/m'

h = Cp•T

Thus,

Cp•T1 + Q/m' = Cp•T2 + W/m'

Plugging in the relevant values, we have;

(1*300) - (80/10) = (1*T2) - (130/10)

Q and M negative because heat is being lost.

300 - 8 + 13 = T2

T2 = 305 K = 305 - 273 °C = 32 °C

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The sharpest bend that can be placed in a piece of metal without critically weakening the part is called the?
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Answer:

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