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lana [24]
3 years ago
10

A hot brass plate is having its upper surface cooled by impinging jet of air at temperature of 15°C and convection heat transfer

coefficient of 220 W/m^2•K. The 10-cm thick brass plate (rho = 8530 kg/m^3, cp = 380 J/kg•K, k = 110 W/m•K, and α = 33.9×10^–6 m^2/s) has a uniform initial temperature of 900°C, and the bottom surface of the plate is insulated.
Required:
Determine the temperature at the center plane of the brass plate after 3 minutes of cooling.
Engineering
1 answer:
gulaghasi [49]3 years ago
5 0

Answer:

809.98°C

Explanation:

STEP ONE: The first step to take in order to solve this particular Question or problem is to find or determine the Biot value.

Biot value = (heat transfer coefficient × length) ÷ thermal conductivity.

Biot value = (220 × 0.1)÷ 110 = 0.2.

Biot value = 0.2.

STEP TWO: Determine the Fourier number. Since the Biot value is greater than 0.1. Tis can be done by making use of the formula below;

Fourier number = thermal diffusivity × time ÷ (length)^2.

Fourier number = (3 × 60 × 33.9 × 10^-6)/( 0.1)^2 = 0.6102.

STEP THREE: This is the last step for the question, here we will be calculating the temperature of the center plane of the brass plate after 3 minutes.

Thus, the temperature of the center plane of the brass plane after 3 minutes = (1.00705) (0.89199) (900- 15) + 15.

= > the temperature of the center plane of the brass plane after 3 minutes = 809.98°C.

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A rectangular bar of length L has a slot in the central half of its length. The bar has width b, thickness t, and elastic modulu
Naya [18.7K]

Answer:

The correct answer to the following question will be "1.23 mm".

Explanation:

The given values are:

Average normal stress,

\sigma=200 \ MPa

Elastic module,

E = 77 \ GPa

Length,

L = 570 \ mm

To find the deformation, firstly we have to find the equation:

⇒  \delta=\Sigma\frac{N_{i}L_{i}}{E \ A_{i}}

⇒     =\frac{P(\frac{L}{H})}{E(bt)} +\frac{P(\frac{L}{2})}{E (bt)(\frac{2}{3})}+\frac{P(\frac{L}{H})}{Ebt}

On taking "\frac{PL}{Ebt}" as common, we get

⇒     =\frac{\frac{PL}{Ebt}}{[\frac{1}{4}+\frac{3}{4}+\frac{1}{4}]}

⇒     =\frac{5PL}{HEbt}

Now,

The stress at the middle will be:

⇒  \sigma=\frac{P}{A}

⇒     =\frac{P}{(\frac{2}{3})bt}

⇒     =\frac{3P}{2bt}

⇒  \frac{P}{bt} =\frac{2 \sigma}{3}

Hence,

⇒  \delta=\frac{5 \sigma \ L}{6E}

On putting the estimated values, we get

⇒     =\frac{5\times 200\times 570}{6\times 77\times 10^3}

⇒     =\frac{570000}{462000}

⇒     =1.23 \ mm  

8 0
3 years ago
Water is the working fluid in a Rankine cycle with reheat. The turbine and the pump have isentropic efficencies of 80%. Superhea
zheka24 [161]

Answer:

A)  3783.952 kJ/kg

B)  34.5%

C)  2476.67 kJ/kg

Explanation:

A) Determine the rate of heat addition entering the first-stage turbine

Qin ( 1st stage ) =  ( h1 - h6 ) + ( h3 - h2 )

                         = ( 3321.4 - 164.07 ) + ( 3438.566 - 2811.944 )

                         = 3783.952 kJ/kg

<em>h values are gotten from super heated table </em>

B) Determine the thermal efficiency

n = 34.5%

attached below

C) Rate of heat transfer from working fluid passing through the condenser to the cooling water

Qout = h4 - h5

         = 2628.2 - 151.53

         = 2476.67 kJ/kg

8 0
3 years ago
Another focus of effective communication, according to Stephen Covey, is ensuring that:
svetoff [14.1K]

Answer:

Stephen Covey believes this principle is the key to effective interpersonal communication. Seek first to understand, then to be understood. This habit is about communicating with others. It's about developing the habit of listening carefully and really understanding the other person BEFORE giving your thoughts.

Explanation:

4 0
3 years ago
Read 2 more answers
Steam enters an insulated turbine at 100 bar, 400oC. At the exit, the pressure and quality are 200 kPa and 0.47, respectively. D
OverLord2011 [107]

Answer:

power produced = 3098.52 kW

Explanation:

given data

insulated turbine = 100 bar

temperature = 400°C

pressure = 200 kPa

mass flow rate = 1.99 kg/s

solution

we use here steam table for At 100 bar and 400°C  

h1 = 3096.5 KJ/Kg

and  

at P2 = 200 Kpa

h2 = hf + 0.47 hg

h2 = 504.7 + 0.47 ×  2201.6  

h2 = 1539.452 KJ/Kg

so here

power produced  is express as

power produced = m × (h1 - h2)    .................1

power produced = 1.99 × ( 3096.5 - 1539.452 )

power produced = 3098.52 kW

8 0
3 years ago
THE MASS FOR OBJECT 1 is 107.01 grams what is the objects force in Newton’s answer please
Aleksandr [31]

Given that,

Mass of the object 1, m = 107.01 grams

To find,

Force on the object.

Solution,

The force acting on the object is gravitational force. The force is given by the formula as follow :

F = mg

g is acceleration due to gravity

F = 0.10701 kg × 9.8 m/s²

F = 1.048 N

So, the force acting on object 1 is 1.048 N.

5 0
3 years ago
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