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mel-nik [20]
3 years ago
8

Why is kinetic friction less than static?

Physics
1 answer:
alekssr [168]3 years ago
7 0
The kinetic friction is usually not greater than the applied force. Keep applying more force until you reach a maximum value for the static friction
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What is the acceleration of a proton moving with a speed of 7.0 m/s at right angles to a magnetic field of 1.7 t ?
Ivenika [448]
We know that a charge moving in a magnetic field is subject to the force:
F = q · v · B

But we also know that:
F = m · a

Therefore, it must be:
m · a = <span>q · v · B

And solving for a:
</span>a = <span>q · v · B / m

Recall that for a proton:
q = 1.6</span>×10⁻¹⁹ C
m = 1.673×10⁻²⁷ kg

Now, you can find:
a = 1.6×10⁻¹⁹ · 7.0 · 1.7 / <span>1.673×10⁻²⁷
   = 1.14</span>×10⁹ m/s²

Hence, the acceleration of the proton is 1.14<span>×10⁹ m/s²</span>.
8 0
3 years ago
In Millikan's oil drop experiment an oil drop is at rest between two large plates separated by 1.3 cm when the potential differe
sweet-ann [11.9K]

Answer:

Mass of the oil drop, m=3.01\times 10^{-15}\ kg

Explanation:

Potential difference between the plates, V = 400 V

Separation between plates, d = 1.3 cm = 0.013 m

If the charge carried by the oil drop is that of six electrons, we need to find the mass of the oil drop. It can be calculated by equation electric force and the gravitational force as :

qE=mg

m=\dfrac{qE}{g}

q=6e, e is the charge on electron

E is the electric field, E=\dfrac{V}{d}=\dfrac{400}{0.013}=30769.23\ V/m

m=\dfrac{6\times 1.6\times 10^{-19}\times 30769.23}{9.8}

m=3.01\times 10^{-15}\ kg

So, the mass of the oil drop is 3.01\times 10^{-15}\ kg. Hence, this is the required solution.

5 0
3 years ago
A cannonball is shot from the top of a 30
lyudmila [28]

Answer:

C) 19 m/s

Explanation:

The motion of the cannonball is a projectile motion, which consists of 2 independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion (constant acceleration) along the vertical direction

As a result, we have the following:

- The horizontal velocity of the cannonball remains constant during the motion, and it is given by

v_x = u cos \theta

where

u = 25 m/s is the initial velocity

\theta=40^{\circ} is the angle

Substituting,

v_x = (25)(cos 40^{\circ})=19 m/s

- The vertical velocity keeps changing during the motion due to the acceleration of gravity. However, at the top of the trajectory, the vertical velocity is zero:

v_y = 0

This means that at the top of its path, the cannonball has only horizontal velocity, so its velocity is

C) 19 m/s

3 0
3 years ago
It takes 300 newtons of force and a distance of 20 meters for a moving car to come to stop
Andrei [34K]
The answer is 15 I think.
7 0
4 years ago
PLS HELP I WILL GIVE BRAINLIEST TO FIRST ANSWER
Gekata [30.6K]

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Hope this is helpfull

Explanation:

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