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gayaneshka [121]
3 years ago
15

A solenoid of length 2.50 cm and radius 0.750 cm has 25 turns. If the wire of the solenoid has 1.85 amps of current, what is the

magnitude of the magnetic field inside the solenoid
Physics
1 answer:
vfiekz [6]3 years ago
4 0

Answer:

13.875 T

Explanation:

Parameters given:

Length of solenoid, L = 2.5 cm = 0.025 m

Radius of solenoid, r = 0.75 cm = 0.0075 m

Number of turns, N = 25 turns

Current, I = 1.85 A

Magnetic field, B, is given as:

B = (N*r*I) /L

B = (25 * 0.0075 * 1.85)/0.025

B = 13.875 T

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Answer:

166 W

Explanation:

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\text{Power} = \dfrac{\text{Work done}}{\text{time}}

The work done by Jill is the product of the weight of the pail and the height it moves.

The weight is the product of the mass and acceleration of gravity, <em>g</em>. Taking <em>g</em> as 9.81 m/s², the weight is

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2 years ago
PLZ HELP I WILL GIVE BRAINLIEST
Vaselesa [24]

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12.7m/s

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We know that the Moon revolves around Earth during a period of 27.3 days. The average distance from the center of Earth to the c
PtichkaEL [24]

Answer:

Explanation:

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Given radius (r)=3.84×10^8m

Circular motion formulas

V=wr

a=v^2/r

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Now, the moon makes one complete oscillation for 27.3days

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