Answer:
0.44g
Explanation:
Given parameters:
Mass of magnesium hydroxide = 0.645g
Solution
The balanced reaction equation is shown below:
Mg(OH)₂ → MgO + H₂O
From the equation above, we see that the number of atoms are conserved.
To find the mass of magnesium oxide produced, we find the number moles of the decomposed magnesium hydroxide first:
Molar mass of Mg(OH)₂ = 24 + 2(16+1) = 58g/mol
Number of moles of Mg(OH)₂ = 
= 
= 0.011mole
Now, from the balanced equaiton, we know that:
1 mole of Mg(OH)₂ produces 1 mole of MgO
Therefore, 0.011mole of Mg(OH)₂ will produce 0.011mole of MgO
so mass of MgO = number of moles of MgO x molar mass of MgO
Molar mass of MgO = 24 + 16 = 40g/mol
mass of MgO = 0.011 x 40 = 0.44g
Answer: The four 
hybridized orbitals on Sb makes up the sigma bonds between Sb and F in antimony(iii) fluoride ,
Explanation:
According to VESPR theory:
Number of electrons around the central atom : ![\frac{1}{2}[V+N-C+A]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5BV%2BN-C%2BA%5D)
V = number of valence electrons
N = number of neighboring atoms
C = charge on cation
A = charge on an anion
In antimony(III) fluoride ,
Antimony being central atom: V= 5,N =3,C=0,A=0
Number of electrons : ![\frac{1}{2}[V+N-C+A]=4](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5BV%2BN-C%2BA%5D%3D4)
Number of electrons around the central atom are 4 which means that molecule has four hybridized orbitals.
Answer:
Reactant : A combustion of hydrocarbon.
Explanation:
It is known that when hydrocarbons are involved in combustion, they produce carbon dioxide and water.
CxHy + (x+y/4)O2 ===> xCO2 + y/2H2O
1. Make sure it isnt something other than a ghost(i.e. something falling)
2. Record what you see and hear
3. See if anyone hears the same thing as you(unless your home alone)
4. Be confident and dont be fearful because ghost sense fear
5. Pray or perform an exorsism( if this is part of your religion)
6. After the ghost leaves, clean up.( like literally mops the floors and stuff. it keeps the ghosts out)
Good Luck ! :]
What is the increment of change in a series of straight-chain alkanes?
CH
CH3
CH4
CH2
Answer:
CH2
