The outer layers are the photosphere the chromosphere the transition region in the corona
Answer: 
Explanation:
According to ideal gas equation:
P = pressure of gas = 0.987 atm
V = Volume of gas = 12 L
n = number of moles = 0.50
R = gas constant =
T =temperature = ?
Thus the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L is
Answer:
The correct answer is - 1, 2, and 4 statements.
Explanation:
Beta and gamma turns are common plots or turns in proteins and contain intra-turn hydrogen bonds. This hydrogen bond is present between CO of residue i and NH of residue i+3 that holds the confirmation in beta turns.
Beta turns, assist the protein to get their globularity, as the aim of beta turns is to reverse the direction of the polypeptide. The two main of beta turns are type-I and type-Il. and their minor images are type-I and type-Il.
Thus, the correct answer is - 1, 2, and 4 statements.
Answer: CF4
Explanation:
Calculate the molar mass of each compound. Divide the molar mass of Carbon by the molar mass of each compound, then multiply the answer by 100 to get the percentage.
CF4= 12+(19X 4)
=12+76= 88 g/mol
%C= 12/88 x 100= 13.64%
CO2= 12+(16 X 2)
12+32= 44 G/MOL
%C= 12/44 x 100= 27.3%
CH4= 12+ (1 X4)
=12+4
=16 G/MOL
%C= 12/16 X 100= 75%
C204
(12X2) + (16X4)
24+64
= 88 g/mol
%C= 24/88 x 100
= 27.3%
Answer:
0.43.
Explanation:
In order to solve this question we will need the an equation called Henderson-Hasselbalch Equation. The Henderson-Hasselbalch Equation can be represented by the reaction below;
pH= pKa + log ( [ A^- ] / [ HA] ).
Where HA is the acetic acid and A^- is the Acetate ion
We are given the pH value to be = 4.38 and the ka to be = 1.76×10^–5. So, we will use the value for the ka to find the pKa through the formula below.
pKa = - log ka.
Therefore, pKa = - log( 1.76×10^–5).
pKa= 4.75 + log
So,
4.38 = 4.75 + log ([ A^-] / [HA]).
4.38 - 4.75 = log ( [ A^- ] / [ HA] ).
( [ A^- ] / [ HA] ) = 10^- 0.37.
( [ A^- ] / [ HA] ) = 0.42657951880159265.
( [ A^- ] / [ HA] )= 0.43.
