The average atomic mass of the element is the sum of the products of the percentage abundance of isotope and its mass number. Therefore, for atomic mass equal to 58.933, the most abundant isotope is cobalt-59. Thus, the answer is letter C.
1m = 100cm
so 10m = 100*10 = 1000cm or in scientific notation 1.00x10^3 cm
1g = 1/1000kg
1mL = 1/1000L
so 1g/mL = (1/1000)/(1/1000)kg/L
=1kg/L
37.5g/mL = 37.5kg/L or 3.75*10^1 kg/L
Answer:
4.37 g of barium sulphate
Explanation:
The reaction equation is;
3BaCl2(aq) + Fe2(SO4)3(aq) ---->3 BaSO4(s) + 2FeCl3(aq)
From the question, the number of moles of both barium chloride and FeSO4 = 125/1000 L × 0.150 M = 0.01875 moles
To find the limiting reactant;
3 moles of barium chloride yields 3 moles of barium sulphate
0.01875 moles of barium chloride yields 3 × 0.01875 moles/3 = 0.01875 moles of barium sulphate
1 mole of iron III sulphate yields 3 moles of barium sulphate
0.01875 molesof iron III sulphate yields 0.01875 moles ×3/1 = 0.05625 moles of barium sulphate
Hence,barium chloride is the limiting reactant
Amount of barium sulphate produced = 0.01875 moles × 233 g/mol = 4.37 g of barium sulphate
In order to find out the ranking of ions basicity, check the
pKa values of each ions. The principle that you need to remember is that the
stronger the acid the weaker the corresponding conjugate base. The pKa dictates
acid value of the compound. The answer would be CH3NH, CH3O-, and CH3CH2-.
B is the correct answer to select
