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crimeas [40]
3 years ago
6

How much work does gravity do on the compressor during this displacement?

Physics
2 answers:
gayaneshka [121]3 years ago
6 0

Explanation and Examples

let the mass of the compressor be

mass (m):

height in x axis is (h1)

height in y axis be (h2):

Height difference: h2-h1

displacement x force:

mass x gravity x height

(m)*9.8*(height difference) = ___ J

Since gravity is forcing down, it would be negative!

Put the values that you require and get the answer.

evablogger [386]3 years ago
4 0

Answer:

W = mg × (r₂ - r₁)

Explanation:

Work done is the product of force acting and the displacement. In this case, we have to find the work done by the gravity on the compressor during displacement.

Let r₁ and r₂ are the initial and the final position of the body. So, displacement will be, r₂ - r₁.

Work done, W = F × d

Since, F = mg

W = mg × (r₂ - r₁)

Hence, the work done by the gravity on the compressor is " mg × (r₂ - r₁) Joules".

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Spaceship 1 and Spaceship 2 have equal masses of 300kg. They collide. Spaceship 1's final speed is 3 m/s, and Spaceship 2's fina
fiasKO [112]

Answer:

B. 1500 kg*m/s

Explanation:

Momentum p = m* v

In any type of collision, the total momentum is preserved!

The total momentum before and the total momentum after the collision is the same. We know the mass and speed after the collision so we can calculate the total momentum.

p1 + p2 =

m1*v1 + m2*v2

m1 = me = 300 kg

v1 = 3 m/s

v2 = 2 m/s

Substitute the given numbers:

300*3 + 300+2

900 + 600

1500 kg*m/s, which is answer B.

3 0
3 years ago
Is the relationship between the length of a pendulum and its period is valid at all times?
Stels [109]
Yes it is valid all the times under the consideration of acceleration due to gravity .it is not valid on space where there is no influence of gravity
4 0
3 years ago
Is it possible for an object that has a constant negative acceleration to change the direction in which it is moving? Explain wh
lozanna [386]
Yes! I think there are two ways you could go with this answer: 1) Acceleration is the change in velocity over time, it can be negative or positive. If you have an object that is already moving forwards in a straight line and give it a constant negative acceleration, it will slow down and then start going in reverse. 2)Velocity is a vector, meaning it has both magnitude and direction. In the example above, the acceleration is due to a change in magnitude, or speed (from +ve to -ve) but not a change in direction. Something that has constant speed but is changing direction is also accelerating (like something that is orbiting). You could use the earth as an example, which is constantly accelerating due to moving in a circle around the sun. At any time in the year you can say that in half a year's time the earth's direction will be reversed.
4 0
2 years ago
How is Coulomb’s law similar to newton’s law of gravitational force? How is it different
natulia [17]

The similarities and the differences between gravitational and electric force are listed below

Explanation:

- The magnitude of the gravitational force between two objects is given by Newton's law of gravitation:

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between them

- Coloumb's law gives instead the strength of the electrostatic force between two charged objects, which is

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

By comparing the two equations, we find the following similarities:

  • Both the forces are inversely proportional to the square of the distance between the two objects, F\propto \frac{1}{r^2}
  • Both the forces are proportional to the product between the "main quantity" of each force, which is the mass for the gravitational force (F\propto m_1 m_2) and the charge for the electric force (F\propto q_1 q_2

Instead, we have the following differences:

  • The gravitational force is always attractive, since the sign of m is always positive, while the electric force can be either attractive or repulsive, since the sign of q can be either positive or negative
  • The value of the gravitational costant G is much smaller than the value of the Coulomb's constant, so the gravitational force is much weaker than the electric force

Learn more about gravitational force and electric force:

brainly.com/question/1724648

brainly.com/question/12785992

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

5 0
3 years ago
A 50-ohm resistor in a 0.5 Amp circuit produces how much voltage drop?​
ahrayia [7]

25 volts

Explanation:

Use Ohm's law to find the potential drop:

V = IR

= (0.5 A)(50 ohms)

= 25 volts

6 0
2 years ago
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