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7 months ago

Calculate the lowest energy (in ev) for an electron in an infinite well having a width of 0.050 mm.

Physics

1 answer:

MA_775_DIABLO [31]7 months ago

7 0

The lowest energy of electron in an infinite well is 1.2*10^-33J.

To find the answer, we have to know more about the infinite well.

<h3>What is the lowest energy of electron in an infinite well?</h3>

It is given that, the infinite well having a width of 0.050 mm.
We have the expression for energy of electron in an infinite well as,

$E_n=\frac{n^2h^2}{8mL^2}$

where;

$m=9.1*10^{-31}kg\\L=0.050*10^{-3}m\\h=6.63*10^{-34}Js\\n=1$

Thus, the lowest energy of electron in an infinite well is,

$E_1=\frac{(6.63*10^{-34})^2}{8*9.1*10^{-31}*(0.050*10^{-3})}=1.2*10^{-33}J$

Thus, we can conclude that, the lowest energy of electron in an infinite well is 1.2*10^-33J.

Learn more about the infinite well here:

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Answer:

Velocity = 131 m/s

Speed = 131 m/s

Explanation:

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2 years ago

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Answer:

Part a)

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Part b)

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Part c)

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Explanation:

Part a)

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so we have

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now we have

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Part b)

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Part c)

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Part d)

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2 years ago

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Answer:

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