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umka2103 [35]
1 year ago
4

The following techniques are used to separate mixtures. A simple distillation B fractional distillation D chromatography E filtr

ation From this list, choose the most suitable technique to separate the following. (a) methane from a mixture of the gases, methane and ethane. ​
Chemistry
1 answer:
tester [92]1 year ago
8 0

Answer: The answer is B fractional distillation.

Explanation:

Individual components of a mixture can be separated out by a number of methods. These are:

gravity separation: If the various components of the mixture have different gravity, they will form different layers (when shaken and allowed to settle). This way they can be separated out.

Filtration: Particles of different

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Which energy transformation occurs in an<br> electric motor?
vivado [14]

Answer:

Electrical energy to mechanical energy

Explanation:

In an electric motor, the energy transformation that is involve is a move from from electrical energy to mechanical energy.

For every system, according to the law of conservation of energy "energy is neither created nor destroyed but transformed from one form to another".

  • An electric motor converts electrical energy to mechanical energy
  • The electrical energy passes through and electromagnet set up.
  • This then cause the motion to rotate.
  • Therefore, electrical energy is transformed to mechanical energy.
5 0
3 years ago
A strong acid with a concentration of 0.01 Mol/L would have a pH of __________.
BARSIC [14]

Answer:

2

Explanation:

the pH of the strong acid solution will be

pH = -log[H+] = -log[0.01] =  2

5 0
4 years ago
How many moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas?
tino4ka555 [31]

Taking into account the reaction stoichiometry, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CO₂ + 4 H₄  → CH₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CO₂: 1 mole
  • H₄: 4 moles  
  • CH₄: 1 mole
  • H₂O: 2 moles

<h3>Moles of CH₄ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?

moles of CH_{4} =\frac{85.1 moles of CO_{2}x4 moles of CH_{4} }{1 moles of CO_{2}}

<u><em>moles of CH₄= 340.4 moles</em></u>

Then, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

6 0
2 years ago
12. How many grams of glucose (C6H1206) is produced if 17.3 mol of H20 is reacted according to this
iren2701 [21]

Answer:

1. 17.3 MOLES OF WATER WILL PRODUCE 518.4 G OF GLUCOSE.

2. 87.4 G OF HNO3 WILL PRODUCE 7.86 G OF NITROGLYCERIN WHEN REACTED WITH EXCESS GLYCEROL.

Explanation:

1. How many grams of glucose is produced from 17.3 mole of water?

Equation:

6CO2 + 6H20 ------> C6H12O6 + 6O2

From the reaction, 6 moles of carbon dioxide reacts with 6 moles of water to produce 1 mole of glucose

So therefore,

6 moles of water = 1 mole of glucose

Since 17.3 mole of water was used, we can first calculate the number of moles of glucose produced:

Then, we have:

6 moles of water = 1 mole of glucose

17.3 moles of water = ( 17.3 * 1/ 6) moles of glucose

= 2.883 moles of glucose

So we say 17.3 moles of water produces 2.883 moles of glucose

At standard conditions, 1 mole of a substance is its molar mass

Molar mass of water = 18 g/mol

Molar mass of glucose = 180 g/mol

From the reaction:

17.3 moles of water produces 2.883 moles of glucose

17.3 * 18 g of water produces 2.833 * 180 g of glucose

= 518.94 g of glucose.

From 17.3 mole of water, 518.4 g of glucose will be produced.

2.

C3H5(OH)3 + 3HNO3 -------> C3H5(ONO2)3 + 3H20

3 moles of HNO3 reacts to produce 1 mole of nitroglycerin

Molar mass of HNO3 = ( 1 + 14 + 16*3) = 63 g/mol

Molar mass of nitroglycerin = ( 12 *3 + 1 *5 + 16*6 + 14*3) = 179 g/mol

3 moles of HNO3 = 1 mole of nitroglycerin

3 * 63 g of HNO3 = 179 g of nitroglycerin

if 87.4 g of HNO3 were to be reacted, we have:

189 g of HNO3 = 179 g of nitroglycerin

87.4 g of HNO3 = ( 87.4 * 179 / 189) of nitroglycerin

= 7.86 g of nitroglycerin

So therefore, 87.4 g of HNO3 will produce 7.86 g of nitroglycerin when reacted with excess glycerol.

4 0
4 years ago
Where would (aq) (s) go in Cr(NO3)3+K3PO4
Ivenika [448]

Answer:

Cr(NO3)3 (aq) +K3PO4 (s)

Explanation:

7 0
3 years ago
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