Question

The vapor pressure of water at 25°C is 3. 13×10^-2 atm, and the heat of vaporization of water at 25°C is 4. 39×10^4 J/mol. Calculate the vapor pressure of water at 61°C.

Answer 1

The vapour pressure of water at 61°C is 1.28x10⁻³

Vapour pressure of a pure compound is the pressure characteristic at any given temperature of a vapour in equilibrium with its liquid or solid form

                                    Kp=P H 2O =0.0313.

But

                                          K p=K c(RT)

                                          Δn=K c

                                     (RT) because Δn=1.

Substitute values,

                                     0.0313=K c (0.0821×298)

                                          K c =1.28×10 −3 .

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