Explanation:
It is given that,
Magnitude of magnetic field, B = 0.35 T
Side of square, a = 0.2
Area of square, 
Angle between field and normal of the surface is 35 degrees. So, the angle between the magnetic field and area is, 
We need to find the flux through the loop. Magnetic flux is given by :
or
Hence, this is the required solution.
1/f= 1/di+1/do
1/f=1/90m+1/40m
1/f ≈27.7m
Answer:
6 m/s²
Explanation:
From the question given above, the following data were obtained:
Velocity (v) = 30 m/s
Time (t) = 5 s
Acceleration (a) =..?
Acceleration is defined mathematically as:
Acceleration (a) = Velocity (v) /time (t)
a = v /t
With the above formula, we can obtain the acceleration of the object as follow:
Velocity (v) = 30 m/s
Time (t) = 5 s
Acceleration (a) =..?
a= v/t
a= 30/5
a = 6 m/s²
Therefore, the acceleration of the object is 6 m/s² due East.
